Chapter 23, Problem 89GQ

(a)

Interpretation Introduction

Interpretation:

The products and chemical equation has to be written for the reactions of ${\text{CH}}_{\text{2}}=\text{CH}-{\text{CH}}_{\text{2}}\text{OH}$ with ${\text{H}}_{\text{2}}$(hydrogenation, in presence of a catalyst).

Concept Introduction:

Hydrogenation:

Palladium on carbon (Pd/C) is used as a catalyst for hydrogenation of alkenes and alkanes.

In general, an alkene undergo hydrogentaion reaction when it is treated with hydrogen gas. The addition of two hydrogen atoms takes place on the carbon-carbon double bond.

(b)

Interpretation Introduction

Interpretation:

The products and chemical equation has to be written for the reactions of ${\text{CH}}_{\text{2}}=\text{CH}-{\text{CH}}_{\text{2}}\text{OH}$ with excess oxidizing agent.

Concept Introduction:

A primary alcohol gives carboxylic acid $\left(\text{RCOOH}\right)$ in presence of excess oxidizing agent. However, a secondary alcohol gives ketone in presence of excess oxidizing agent. A tertiary alcohol does not undergo oxidation reaction.

(c)

Interpretation Introduction

Interpretation:

The products and chemical equation has to be written for the reactions of ${\text{CH}}_{\text{2}}=\text{CH}-{\text{CH}}_{\text{2}}\text{OH}$ with Addition polymerization.

Concept Introduction:

The polymerisation reaction of given monomer ${\text{CH}}_{\text{2}}=\text{CH}-{\text{CH}}_{\text{2}}\text{OH}$ unit gives polymeized product. The product is an addition polymer as during polymerisation its monomer units combine directly.

(d)

Interpretation Introduction

Interpretation:

The products and chemical equation has to be written for the reactions of ${\text{CH}}_{\text{2}}=\text{CH}-{\text{CH}}_{\text{2}}\text{OH}$ with acetic acid forms an ester.

Concept Introduction:

Esters are prepared by the condensation reaction of carboxylic acids and alcohols. One mole of each acid and alcohol undergo condensation reaction which produce one mole of ester.