Principles of Instrumental Analysis
7th Edition
ISBN: 9781305577213
Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher: Cengage Learning
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Chapter 24, Problem 24.12QAP
Interpretation Introduction
Interpretation:
A coulometric titration curve needs to be constructed containing 100.0 mL of a 1 M H2SO4 solution in which Fe(II) is titrated against Ce(IV) which is generated from 0.075 M Ce(III).
Concept introduction:
In coulometric titrations, a constant current is used to generate the titrant electro-analytically. In some coulometric titrations the analyte may be directly involved at the generator electrode. For example, the coulometric titration of Fe(II) in part by electro-analytically generated Ce(IV) and in part by direct electrode reaction.
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Calculate the potential in the solution (vs. NHE) in the titration of 50.0 mL of 0.100 M Fe2+in 1.00 M HClO4 with 0.0167 M Cr2O7 2− at 10, 25, 50 and 60 mL titrant added.
Calculate the potential of the solution in the titration of 50.0 mL 0.100 M Fe2+ in 1.00 M HClO4 with 0.0167 M Cr2O72- at 10.00 mL titrant added.
Given: You weigh out exactly 0.200 g of Fe(NH4)2(SO4)2·6H2O and dissolve it in the 100.00 mL volumetric flask. You then pipette 2.00 mL of this solution into the 50.00 mL volumetric flask to prepare the stock standard tris-bipyridyl-iron(II) solution.
a. Calculate the molar concentration of iron(II) in this solution in the 50.00 mL volumetric flask. (The MW of Fe(NH4)2(SO4)2·6H2O is 392.14 g/mol)
(answer a given the information above)
Chapter 24 Solutions
Principles of Instrumental Analysis
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