Chapter 24, Problem 24.55P

Interpretation Introduction

(a)

Interpretation:

The product of the given reaction is to be determined.

Concept introduction:

In each of these reactions, $\text{C}\equiv \text{C or C=C}$ react. A $\text{syn 1, 2-diol}$ is formed when $\text{C=C }$ is treated with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature or with ${\text{OsO}}_{\text{4}}$. A $\text{1, 2-diketone}$ is formed when an internal $\text{C}\equiv \text{C}$ is treated with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature or with ${\text{OsO}}_{\text{4}}$.

Answer to Problem 24.55P

The given reaction is as follows:

Explanation of Solution

In this reaction, $\text{C=C }$ reacts, indicated by a squiggly line. A $\text{syn 1, 2-diol}$ is formed when C=C is treated with ${\text{OsO}}_{\text{4}}$/${\text{H}}_{\text{2}}{\text{O}}_{\text{2}}\text{,}{\left({\text{CH}}_{\text{3}}\right)}_{\text{3}}\text{COH}$.

Conclusion

The given reaction is explained as when $\text{C=C }$ reacts with ${\text{OsO}}_{\text{4}}$ it produces $\text{syn 1, 2-diol}$.

Interpretation Introduction

(b)

Interpretation:

The product of the given reaction is to be determined.

Concept introduction:

In each of these reactions, $\text{C}\equiv \text{C or C=C}$ reacts. A $\text{syn 1, 2-diol}$ is formed when $\text{C=C }$ is treated with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature or with ${\text{OsO}}_{\text{4}}$. A $\text{1, 2-diketone}$ is formed when an internal $\text{C}\equiv \text{C}$ is treated with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature or with ${\text{OsO}}_{\text{4}}$.

Answer to Problem 24.55P

The given reaction is as follows:

Explanation of Solution

In this reaction, the $\text{C=C }$ reacts, indicated by a squiggly line. A $\text{syn 1, 2-diol}$ is formed when C=C is treated with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature (${\text{0 }}^{\text{o}}\text{C}$).

Conclusion

The given reaction is explained as when $\text{C=C }$ reacts with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature (${\text{0 }}^{\text{o}}\text{C}$)it produces $\text{syn 1, 2-diol}$.

Interpretation Introduction

(c)

Interpretation:

The product of the given reaction is to be determined.

Concept introduction:

In each of these reactions, $\text{C}\equiv \text{C or C=C}$ reacts. A $\text{syn 1, 2-diol}$ is formed when $\text{C=C }$ is treated with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature or with ${\text{OsO}}_{\text{4}}$. A $\text{1, 2-diketone}$ is formed when an internal $\text{C}\equiv \text{C}$ is treated with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature or with ${\text{OsO}}_{\text{4}}$.

Answer to Problem 24.55P

The given reaction is as follows:

Explanation of Solution

In this reaction the $\text{C=C }$ reacts, indicated by a squiggly line. A $\text{syn 1, 2-diol}$ is formed when C=C is treated with ${\text{OsO}}_{\text{4}}$/${\text{H}}_{\text{2}}{\text{O}}_{\text{2}}\text{,}{\left({\text{CH}}_{\text{3}}\right)}_{\text{3}}\text{COH}$.

Conclusion

The given reaction is explained as when $\text{C=C }$ reacts with ${\text{OsO}}_{\text{4}}$ it produce a $\text{syn 1, 2-diol}$.

Interpretation Introduction

(d)

Interpretation:

The product of the given reaction is to be determined.

Concept introduction:

In each of these reactions, $\text{C}\equiv \text{C or C=C}$ reacts. A $\text{syn 1, 2-diol}$ is formed when $\text{C=C }$ is treated with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature or with ${\text{OsO}}_{\text{4}}$. A $\text{1, 2-diketone}$ is formed when an internal $\text{C}\equiv \text{C}$ is treated with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature or with ${\text{OsO}}_{\text{4}}$.

Answer to Problem 24.55P

The given reaction is as follows:

Explanation of Solution

In this reaction $\text{C}\equiv \text{C}$ the reacts, indicated by a squiggly line. A $\text{1, 2-diketone}$ is formed when $\text{C}\equiv \text{C}$ is treated with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in cold temperature (${\text{0 }}^{\text{o}}\text{C}$).

Conclusion

The given reaction is explained as when $\text{C}\equiv \text{C}$ reacts with ${\text{KMnO}}_{\text{4}}\text{/KOH}$ in a cold temperature (${\text{0 }}^{\text{o}}\text{C}$) it produce a $\text{1, 2-diketone}$.