EBK CONCEPTS OF GENETICS
12th Edition
ISBN: 9780134818979
Author: Killian
Publisher: YUZU
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Chapter 25, Problem 18PDQ
Summary Introduction
To determine: The mean weight of the progeny if tomato plants have mean fruit weight of 60g, h2 is 0.3, and fruit average mean value of parents is 80g.
Introduction: Heritability is the measure of the extent to which genes are inherited from parents. It is a narrow sense heritability value obtained by selective breeding. By measuring the response of selective breeding in the offspring, one can estimate the value of realized heritability.
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In a population of tomato plants, mean fruit weight is 60 g and h2 is 0.3. Predict the mean weight of the progeny if tomato plants whose fruit averaged 80 g were selected from the original population and interbred.
The phenotypic data below are the shoot lengths of 25 F1 and 25 F2 rice plants atseedling stage, produced from the cross of IR29 and Hasawi rice varieties. The mean lengths of the shoot from IR29 and Hasawi are 23.1 cm and 46.7 cm, respectively. Tabulate and plot the frequency distributions of the F1 and F2 generations. From each distribution calculate the mean, the variance,and the standard error of the mean. What is the main difference between F1 and F2 distributions?
Formulas needed:Range (R) = maximum – minimum (Use the same no. of decimal places as original data.)No. of phenotypic classes (K) = 1 + 3.3logn (Round up answer to an integer. Number may still be increased or decreased as needed.)n = total no. of valuesClass interval (CI) = R/K (Use the same no. of decimal places as original data.)
The phenotypic data below are the shoot lengths of 25 F1 and 25 F2 rice plants at seedling stage, produced from the cross of IR29 and Hasawi rice varieties. The mean lengths of the shoot from IR29 and Hasawi are 23.1 cm and 46.7 cm, respectively. Tabulate and plot the frequency distributions of the F1 and F2 generations. Use the formulas below in the computations. From each distribution calculate the mean, the variance, and the standard error of the mean. Round off answers to two decimal places. What is the main difference between F1 and F2 distributions?
Chapter 25 Solutions
EBK CONCEPTS OF GENETICS
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- a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…arrow_forwardComplete the punnett square below for a cross between AA and aa A 21 a QUESTION 4 A Aa Complete the punnett square below for a cross between Aa and Aa. 03 Aa Aaarrow_forwardA horticulturist runs a test cross with an offspring (F1 generation) purple plant from Question 8. The phenotypic frequencies of the resulting offspring are 50% white and 50% purple. What is the true genotype of this offspring (F1 generation) purple plant?arrow_forward
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- Consider a corn plant dihybrid for the traits of purple and smooth kernels. When allowed to self-fertilize, 489 offspring are produced. How many of these offspring are expected to exhibit the traits of yellow and smooth kernels?arrow_forwardUse the following information to answer the next question. A Venn Diagram Showing the Relationship Between Oogenesis and Spermatogeneis. Oogenesis 1 NOTE: Similarities are represented by area 2. Differences are represented by areas 1 or 3. Match the numbered regions with the descriptions below. Spermatogenesis 3 Four viable gametes produced: Occurs in gonads: Daughter cells equal in size Unequal cytoplasmic division ▶arrow_forwardUse the following information to answer the next question. In a breeding experiment, a pure plant with round seeds and green pods (RRGG) was crossed with another pure plant with wrinkled seeds and yellow pods (rrgg). The phenotypes of the F2 generation were: 1780 plants with round and green pods, 620 plants with round seeds and yellow pods, 590 plants with wrinkled seeds and green pods and 195 plants with wrinkled seeds and yellow pods. Which law is proved by the result of this experiment? Law of Segregation Law of Mutation Law of Independent Assortment Law of Dominancearrow_forward
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