Bundle: Chemistry for Today: General, Organic, and Biochemistry, Loose-Leaf Version, 9th + LMS Integrated OWLv2, 4 terms (24 months) Printed Access Card
9th Edition
ISBN: 9781337598255
Author: Spencer L. Seager
Publisher: Cengage Learning
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Question
Chapter 25, Problem 25.45E
Interpretation Introduction
Interpretation:
The reason as to why the reaction (b) is not used as a buffer system in the human body is to be stated.
Concept introduction:
A buffer system refers to a solution that could withstand
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Which of the following could be added to a solution of monobasic dihydrogen phosphate (KH2PO4) to produce a buffer? Briefly explain your answer(s).
Dibasic monohydrogen phosphate hydrochloric acid sodium chloride
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(1) H2SO4, NAOH
(2) H2CO3 , KHCO3
Identify and justify the Bronsted-Lowry acid in the reaction: NH3 + HBr à NH4Br(a) NH3 because it is a proton donor (b) HBr because it is a proton donor(c) NH3 because it is a proton acceptor (d) HBr because it is a proton acceptor
Chapter 25 Solutions
Bundle: Chemistry for Today: General, Organic, and Biochemistry, Loose-Leaf Version, 9th + LMS Integrated OWLv2, 4 terms (24 months) Printed Access Card
Ch. 25 - Prob. 25.1ECh. 25 - Prob. 25.2ECh. 25 - Prob. 25.3ECh. 25 - Prob. 25.4ECh. 25 - Prob. 25.5ECh. 25 - What is the principal anion found in the...Ch. 25 - Prob. 25.7ECh. 25 - Prob. 25.8ECh. 25 - Prob. 25.9ECh. 25 - Prob. 25.10E
Ch. 25 - What term is given to the reversible flow of...Ch. 25 - Prob. 25.12ECh. 25 - Prob. 25.13ECh. 25 - Prob. 25.14ECh. 25 - Prob. 25.15ECh. 25 - Prob. 25.16ECh. 25 - Prob. 25.17ECh. 25 - Prob. 25.18ECh. 25 - Prob. 25.19ECh. 25 - Prob. 25.20ECh. 25 - Prob. 25.21ECh. 25 - Prob. 25.22ECh. 25 - Prob. 25.23ECh. 25 - Prob. 25.24ECh. 25 - Prob. 25.25ECh. 25 - Prob. 25.26ECh. 25 - Prob. 25.27ECh. 25 - Prob. 25.28ECh. 25 - Hemoglobin (HHb) is a weak acid that forms the Hb...Ch. 25 - Prob. 25.30ECh. 25 - Prob. 25.31ECh. 25 - Prob. 25.32ECh. 25 - Prob. 25.33ECh. 25 - Prob. 25.34ECh. 25 - Prob. 25.35ECh. 25 - What ionic shift maintains electron charge balance...Ch. 25 - Prob. 25.37ECh. 25 - Prob. 25.38ECh. 25 - Prob. 25.39ECh. 25 - Prob. 25.40ECh. 25 - Prob. 25.41ECh. 25 - Prob. 25.42ECh. 25 - Prob. 25.43ECh. 25 - Prob. 25.44ECh. 25 - Prob. 25.45ECh. 25 - Prob. 25.46ECh. 25 - Prob. 25.47ECh. 25 - Prob. 25.48ECh. 25 - Prob. 25.49ECh. 25 - Prob. 25.50ECh. 25 - Prob. 25.51ECh. 25 - Prob. 25.52ECh. 25 - Prob. 25.53ECh. 25 - Explain how uncontrolled diarrhea can lead to...Ch. 25 - Prob. 25.55ECh. 25 - Prob. 25.56ECh. 25 - Prob. 25.57ECh. 25 - Prob. 25.58ECh. 25 - Prob. 25.59ECh. 25 - The liquid portion of the blood is called: a....Ch. 25 - Prob. 25.61ECh. 25 - Prob. 25.62ECh. 25 - The hormone most responsible for the renal...Ch. 25 - Prob. 25.64ECh. 25 - Prob. 25.65E
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- The concentration of acetylcholine (a neurotransmitter) in a sample can be determined from the pH changes that accompany its hydrolysis. When the sample is incubated with the enzyme acetylcholinesterase, acetylcholine is converted to choline and acetic acid, which dissociates to yield acetate and a hydrogen ion. CНз CHз Нао — сHz— CH "N— снз но-сн— сH,-"N-CH; + CH;— с-о+ н* CH3-C-0- сHз CHз Choline Acetylcholine Acetate In a typical analysis, 11 mL of an aqueous solution containing an unknown amount of acetylcholine had a pH of 7.70. When incubated with acetylcholinesterase, the pH of the solution decreased to 6.89. Assuming there was no buffer in the assay mixture, determine the number of moles of acetylcholine in the 11 mL sample.arrow_forwardFor conjugate acidbase pairs, how are Ka and Kb related? Consider the reaction of acetic acid in water CH3CO2H(aq)+H2O(l)CH3CO2(aq)+H3O+(aq) where Ka = 1.8 105 a. Which two bases are competing for the proton? b. Which is the stronger base? c. In light of your answer to part b. why do we classify the acetate ion (CH3CO2) as a weak base? Use an appropriate reaction to justify your answer. In general, as base strength increases, conjugate acid strength decreases. Explain why the conjugate acid of the weak base NH3 is a weak acid. To summarize, the conjugate base of a weak acid is a weak base and the conjugate acid of a weak base is a weak acid (weak gives you weak). Assuming Ka for a monoprotic strong acid is 1 106, calculate Kb for the conjugate base of this strong acid. Why do conjugate bases of strong acids have no basic properties in water? List the conjugate bases of the six common strong acids. To tie it all together, some instructors have students think of Li+, K+, Rb+, Cs+, Ca2+, Sr2+, and Ba2+ as the conjugate acids of the strong bases LiOH, KOH. RbOH, CsOH, Ca(OH)2, Sr(OH)2, and Ba(OH)2. Although not technically correct, the conjugate acid strength of these cations is similar to the conjugate base strength of the strong acids. That is, these cations have no acidic properties in water; similarly, the conjugate bases of strong acids have no basic properties (strong gives you worthless). Fill in the blanks with the correct response. The conjugate base of a weak acid is a_____base. The conjugate acid of a weak base is a_____acid. The conjugate base of a strong acid is a_____base. The conjugate acid of a strong base is a_____ acid. (Hint: Weak gives you weak and strong gives you worthless.)arrow_forwardMagnesium hydroxide and magnesium citrate function as mild laxatives when they reach the small intestine. Why do magnesium hydroxide and magnesium citrate, two very different substances, have the same effect in your small intestine. (Hint: The contents of the small intestine are basic.)arrow_forward
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