Chapter 25, Problem 44E

Interpretation Introduction

(a)

Interpretation:

Whether $\text{P}$ would undergo ß+ decay or not needs to be determined.

Concept introduction:

Radioactive particle decay to maintain stability. Beta-decay happens when there are too many protons or neutrons in the nucleus which transforms one of the protons or neutrons to others. Beta plus decay involves decay of protons which gets transformed to neutrons, positron, and neutrino. In this case, the daughter nucleus produced will have an atomic number one less than the parent nucleus. It is represented as $\text{β}$.

Interpretation Introduction

(b)

Interpretation:

Whether $\text{K}$ would undergo ß+ decay or not needs to be determined.

Concept introduction:

Radioactive particles undergo decay process to attain stability. If there are too many protons or neutrons in the nucleus, it will undergo beta decay. There are twotypes so beta decay which is beta plus and beta minus. The beta plus is the decay of protons that get transformed to neutrons, positron, and neutrino. In this process, the nucleus obtained has an atomic number one less than the parent nucleus and is represented as $\text{β}$

Interpretation Introduction

(c)

Interpretation:

Whether $\text{Z}\text{n}$ would undergo ß+ decay or not needs to be determined.

Concept introduction:

Radioactive particles decay so as to get a stable structure. Beta-decay happens when the nucleus has many protons and neutrons. The beta plus decay involves the decay of protons which gets transformed to neutrons, positron, the neutrino. Through the beta decay process, the daughter nucleus will have an atomic number less than the parent nucleus. It is indicated as $\text{β}$.