Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 25, Problem 59P
(a)
To determine
The temperature of the filament.
(b)
To determine
The reason for that decrease in resistivity is a concern.
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Consider two wires made of different materials. Wire A has a conductivity of 1.3 × 107 Ω-1m-1, and wire B has a conductivity of 5.1 × 107 Ω-1m-1.
Wire A has a circular cross-section with radius 3.78 mm. If there is an electric field of 0.085 V/m inside it, how much current, in amperes, is flowing through it?
Wire B has a square 3.78 mm × 3.78 mm cross-section. If wire B has the same electric field as Wire A did in part (a), what current, in amperes, would be passing through it?
With a potential difference of 4V across a wire of length 5m and cross section area 1x10-6 m2 there is found to be a current of 12A flowing in the wire.
What is the conductivity of the wire?
Select one:
a. 1.5×107 Siemens
b. 9.6×106 Siemens
c. 6×10-7 Siemens
d. 1.66×107 Siemens
Consider a wire made of copper with conductivity 6.0 × 107 Ω-1m-1, which has a circular cross-section of radius 0.79 mm. In a particular circuit, this wire carries a current of 4.5 A.
a. What is the electric field, in volts per meter, inside this wire?
b. If we replace this wire with a gold one of the same size, with conductivity 4.1 × 107 Ω-1m-1, what will the electric field in the wire be?
Chapter 25 Solutions
Physics for Scientists and Engineers
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