Physics for Scientists and Engineers With Modern Physics
9th Edition
ISBN: 9781133953982
Author: SERWAY, Raymond A./
Publisher: Cengage Learning
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Chapter 25, Problem 8OQ
To determine
The kinetic energy of the electron in electron volts.
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Chapter 25 Solutions
Physics for Scientists and Engineers With Modern Physics
Ch. 25.1 - two points and are located within a region in...Ch. 25.2 - QUICK QUIZ 24.2 The labeled points in Figure 24.4...Ch. 25.3 - In Figure 24.8b, take q2, to be a negative source...Ch. 25.4 - In a certain region of space, the electric...Ch. 25 - Prob. 1OQCh. 25 - Prob. 2OQCh. 25 - Prob. 3OQCh. 25 - Prob. 4OQCh. 25 - Prob. 5OQCh. 25 - Prob. 6OQ
Ch. 25 - Prob. 7OQCh. 25 - Prob. 8OQCh. 25 - Prob. 9OQCh. 25 - Prob. 10OQCh. 25 - Prob. 11OQCh. 25 - Prob. 12OQCh. 25 - Prob. 13OQCh. 25 - Prob. 14OQCh. 25 - Prob. 15OQCh. 25 - Prob. 1CQCh. 25 - Prob. 2CQCh. 25 - When charged particles are separated by an...Ch. 25 - Prob. 4CQCh. 25 - Prob. 5CQCh. 25 - Prob. 6CQCh. 25 - Oppositely charged parallel plates are separated...Ch. 25 - Prob. 2PCh. 25 - Prob. 3PCh. 25 - How much work is done (by a battery, generator, or...Ch. 25 - Prob. 5PCh. 25 - Starting with the definition of work, prove that...Ch. 25 - Prob. 7PCh. 25 - (a) Find the electric potential difference Ve...Ch. 25 - Prob. 9PCh. 25 - Prob. 10PCh. 25 - Prob. 11PCh. 25 - Prob. 12PCh. 25 - Prob. 13PCh. 25 - Prob. 14PCh. 25 - Prob. 15PCh. 25 - Two point charges Q1 = +5.00 nC and Q2 = 3.00 nC...Ch. 25 - Prob. 17PCh. 25 - Prob. 18PCh. 25 - Given two particles with 2.00-C charges as shown...Ch. 25 - Prob. 20PCh. 25 - Four point charges each having charge Q are...Ch. 25 - Prob. 22PCh. 25 - Prob. 23PCh. 25 - Show that the amount of work required to assemble...Ch. 25 - Prob. 25PCh. 25 - Prob. 26PCh. 25 - Prob. 27PCh. 25 - Prob. 28PCh. 25 - Prob. 29PCh. 25 - Prob. 30PCh. 25 - Prob. 31PCh. 25 - Prob. 32PCh. 25 - How much work is required to assemble eight...Ch. 25 - Four identical particles, each having charge q and...Ch. 25 - Prob. 35PCh. 25 - Prob. 36PCh. 25 - Prob. 37PCh. 25 - Prob. 38PCh. 25 - Prob. 39PCh. 25 - Prob. 40PCh. 25 - Prob. 41PCh. 25 - Prob. 42PCh. 25 - Prob. 43PCh. 25 - Prob. 44PCh. 25 - Prob. 45PCh. 25 - Prob. 46PCh. 25 - Prob. 47PCh. 25 - The electric field magnitude on the surface of an...Ch. 25 - Prob. 49PCh. 25 - Prob. 50PCh. 25 - Prob. 51PCh. 25 - Prob. 52PCh. 25 - Prob. 53APCh. 25 - Prob. 54APCh. 25 - Prob. 55APCh. 25 - Prob. 56APCh. 25 - Prob. 57APCh. 25 - Prob. 58APCh. 25 - Prob. 59APCh. 25 - Prob. 60APCh. 25 - Prob. 61APCh. 25 - Prob. 62APCh. 25 - Prob. 63APCh. 25 - Prob. 64APCh. 25 - Prob. 65APCh. 25 - Prob. 66APCh. 25 - Prob. 67APCh. 25 - Prob. 68APCh. 25 - Review. Two parallel plates having charges of...Ch. 25 - When an uncharged conducting sphere of radius a is...Ch. 25 - Prob. 71CPCh. 25 - Prob. 72CPCh. 25 - Prob. 73CPCh. 25 - Prob. 74CPCh. 25 - Prob. 75CPCh. 25 - Prob. 76CPCh. 25 - Prob. 77CP
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- An electric potential exists in a region of space such that V = 8x4 2y2 + 9z3 and V is in units of volts, when x, y, and z are in meters. a. Find an expression for the electric field as a function of position. b. What is the electric field at (2.0 m, 4.5 m, 2.0 m)?arrow_forward(a) Find the potential difference VB required to stop an electron (called a slopping potential) moving with an initial speed of 2.85 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential, Vp/Ve. The answer should be in terms of the proton mass mp and electron mass me.arrow_forward(a) Find the potential difference VB required to stop an electron (called a slopping potential) moving with an initial speed of 2.85 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential, Vp/Ve. The answer should be in terms of the proton mass mp and electron mass me.arrow_forward
- Unreasonable Results A proton has a mass of 1.671027 kg. A physicist measures the proton's total energy to be 50.0 MeV. (a) What is the proton's kinetic energy? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forwardIn nuclear fission, a nucleus splits roughly in half, (a) What is the potential 2.001014 in from a fragment that has 46 protons in it? (b) What is the potential energy in MeV of a similarly charged fragment at this distance?arrow_forward(a) What is the final speed of an electron accelerated from rest through a voltage of 25.0 MV by a negatively charged Van de Graff terminal? (b) What is unreasonable about this result? (c) Which assumptions are responsible?arrow_forward
- Suppose an electron (q = - e= - 1.6 x 10-19 C.m = 9.1 x 10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K+U= 0 K= -U 1 Since K=mv and using the formula for potential energy above, we arrive at an equation for speed: 1/2 Plugging in values, the value of the electron's speed is: x 107 m/s V=arrow_forwardAn electron is accelerated from rest between two parallel plates that are seperated by 2.90 cm. The potential difference between the two plates is 1.13×103 V. If the electron travels from the negative plate to the positive plate, what will be the speed of the electron as it exits through a small hole in the positive plate? 3.39×106 m/s 2.13×107 m/s 1.85×107 m/s 1.99×107 m/sarrow_forwardSuppose an electron (q= -e= -1.6 x 10-19 C,m=9.1x 10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K +U = 0 K = -U Since K- and using the formula for potential energy above, we arrive at an equation for speed: v = ( 51/2 Plugging in values, the value of the electron's speed is: V= x 107 m/sarrow_forward
- Calculate the speed of an electron (in m/s) after it accelerates from rest through a potential difference of 140 V. 7.02e25 m/s The speed of the electron v can be found using the kinetic energy equation, K = 1/2(mv^2). The change in kinetic energy is equal to the work done on the electron, K = W = -U = -qV. Using those two equations, solve for the speed v in terms of the potential V and constants. Remember that the mass of an electron is 9.1e-31 kg and its charge is 1.6e-19 C. Submit Answer Incorrect. Tries 1/2 Previous Triesarrow_forwardA proton is accelerated through a potential difference of 1200 V. What is the proton's speed at the end? (mp 1.67 x 10-27 kg) 4.8 x 10^5 m/s 3.4 x 10^5 m/s O 1.2 x 10^7 m/s O 3.3 x 10^6 m/s 4.1 x 10^6 m/s =arrow_forwardA) An electron is to be accelerated from a velocity of 3.50×106 m/s to a velocity of 9.50×106 m/s . Through what potential difference must the electron pass to accomplish this? B)Through what potential difference must the electron pass if it is to be slowed from 9.50×106 m/s to a halt?arrow_forward
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