Modified Mastering Genetics with Pearson eText -- Standalone Access Card -- for Concepts of Genetics (12th Edition)
Modified Mastering Genetics with Pearson eText -- Standalone Access Card -- for Concepts of Genetics (12th Edition)
12th Edition
ISBN: 9780134839707
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino, Darrell Killian
Publisher: PEARSON
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Chapter 26, Problem 1NST

The ability to taste the compound phenylthiocarbamide (PTC) is controlled by a dominant allele T. Individuals homozygous for the recessive allele t are unable to taste PTC. In a genetics class of 125 students, 88 can taste PTC and 37 cannot. Calculate the frequency of the T and t alleles in this population and the frequency of the genotypes.

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Summary Introduction

To determine: The frequency of the T and t alleles and frequency of the genotypes in the given problem.

Introduction: The Hardy-Weinberg law is a mathematical model developed by the British mathematician, Godfrey H. Hardy and the German physician, Wilhelm Weinberg. This law explains the allele and genotype frequencies in a population; that is, indefinably large, randomly mating, and not subjected to any evolutionary forces like mutation, migration, or selection.

Explanation of Solution

In the given question, the ability to taste the compound phenylthiocarbamide (PTC) is regulated by a dominant allele T. An individual having homozygous recessive allele t cannot taste PTC. In a genetics class, there are 125 students. Out of them, 88 can taste PTC, and 37 cannot.

According to the Hardy-Weinberg equation:

p+q=1p2+q2+2pq=1

Where, p and q represent the frequencies of the alleles T and t, respectively.

The students who can taste the PTC will have genotypes either Tt or TT, and those who cannot taste PTC will have genotype tt.

It is given that,

q2=37125=0.54

Therefore, the frequency of t allele, q =0.54

p=1q=10.54=0.456

Therefore, the frequency of T allele, p =0.456

The frequencies of the genotypes are calculated by using the formula p2+q2+2pq=1 as follows:

Frequency of TT

=p2=(0.456)2=0.208

Frequency of tt

=q2=(0.54)2=0.296

Frequency of Tt

=2pq=2(0.456)(0.544)=0.496

Conclusion

Thus, the frequency of the T and t alleles are 0.456 and 0.54, respectively. The frequency of genotypes TT, tt, and Tt are 0.208, 0.0.296, and 0.496, respectively.

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Students have asked these similar questions
The ability to taste the compound PTC is controlled by a dominant allele T, while individuals homozygous for the recessive allele (t) cannot taste PTC. In a population consisting of 500 individuals, 347 are tasters and 153 are non-PTC tasters. Calculate the frequency of the T and t alleles in this population, and frequency of the genotypes.
The ability to taste the compound PTC is controlled by a dominant allele T, while individuals homozygous for the recessive allele (t) cannot taste PTC. In a population consisting of 500 individuals, 347 are tasters and 153 are non-PTC tasters. Calculate the frequency of the T and t alleles in this population, and frequency of the genotypes. (Please train yourself to use the Hardy-Weinberg equation.)
. In pea plants, height is controlled by a Dominant Allele (T) for Tall Height and by a Recessive Allele (t) for Short Height. If 96% of a population of pea plants have the tall phenotype, calculate the frequencies of dominant allele (T) & recessive (t) alleles. Out of the 96%, what is the estimation of how many are homozygous dominant vs. heterozygous? What is the frequency of the recessive phenotype?

Chapter 26 Solutions

Modified Mastering Genetics with Pearson eText -- Standalone Access Card -- for Concepts of Genetics (12th Edition)

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