The resistivity is given approximately by the expression ρ = ρ 0 e α ( T − T 0 ) .

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Answer 1

Question

Chapter 26, Problem 48CP

(a)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0eα(T−T0) .

(b)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0[1+α(T−T0)] .

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of 20.0°C and satisfies the equation p = Po[1 + a(T - T)], where po is the resistivity of = 20.0°C. Suppose the coefficients were given the symbol B and were based on a T, of 0°C, so that they satisfied the equation p = Po*[1+ B(T - 0°C)], The temperature coefficient of resistivity a is based on a reference temperature the material at To where is the resistivity of the material at 0°C. Obtain the value for the coefficient a from this table and then determine the value of the coefficient B for silver. Po (°C)-1 Need Help? Read It

A more general definition of the temperature coefficient of resistivity is α =1ρ|dρdT|where ρ is the resistivity at temperature T. (a) Assuming α is constant, show that ρ = ρ0eα(T−T0) where ρ0 is the resistivity at temperature T0. (b) Using the series expansion ex ≈ 1 + x for x << 1, show that the resistivity is given approximately by the expression ρ = ρ0[1 + α(T − T0)] for α(T − T0) ≪ 1

If R=Ro[1+ a(T - To)], find: (a) the temperature coefficient of resistivity, a, in terms of R, Ro, T, and To. (b) the temperature coefficient of resistivity for a resistor with resistances of 8.2 at 33°C and 9.35 at 70°C.

Answer 2

Question

Chapter 26, Problem 48CP

(a)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0eα(T−T0) .

(b)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0[1+α(T−T0)] .

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Answer 3

Question

Chapter 26, Problem 48CP

(a)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0eα(T−T0) .

(b)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0[1+α(T−T0)] .

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Answer 4

Question

Chapter 26, Problem 48CP

(a)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0eα(T−T0) .

(b)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0[1+α(T−T0)] .

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Answer 5

Chapter 26, Problem 48CP

(a)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0eα(T−T0) .

(b)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0[1+α(T−T0)] .

Answer 6

Chapter 26, Problem 48CP

(a)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0eα(T−T0) .

Answer 7

Chapter 26, Problem 48CP

(a)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0eα(T−T0) .

Answer 8

(b)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0[1+α(T−T0)] .

Answer 9

(b)

To determine

To show: The resistivity is given approximately by the expression ρ=ρ0[1+α(T−T0)] .

Answer 10

Expert Solution & Answer

Answer 11

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Answer 12

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Answer 13

Ch. 26.1 - Consider positive and negative charges of equal...Ch. 26.2 - Prob. 26.2QQ Ch. 26.2 - Prob. 26.3QQ Ch. 26.4 - When does an incandescent lightbulb carry more...Ch. 26 - Prob. 1P Ch. 26 - A small sphere that carries a charge q is whirled...Ch. 26 - Prob. 3P Ch. 26 - Prob. 4P Ch. 26 - Prob. 5P Ch. 26 - Figure P26.6 represents a section of a conductor...

The resistivity is given approximately by the expression ρ = ρ 0 e α ( T − T 0 ) .

Solution Summary: The author explains how the resistivity is given approximately by the expression rho =

To show: The resistivity is given approximately by the expression ρ=ρ0eα(T−T0) .

To show: The resistivity is given approximately by the expression ρ=ρ0[1+α(T−T0)] .

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Chapter 26 Solutions