Concept explainers
(a)
The speed of orbiting particle.
(a)
Answer to Problem 60PQ
The speed of orbiting particle is
Explanation of Solution
Write an expression for the culoumb force.
Here,
Write an expression for the centripetal force.
Here,
The centripetal force and culoumb force are balances to keep the particle in motion.
Equate equation (I) and (II).
Rearrange equation (III) to find
Conclusion:
Substitute
Thus, the speed of orbiting particle is
(b)
Electric potential energy of the system.
(b)
Answer to Problem 60PQ
Electric potential energy of the system is
Explanation of Solution
Write an expression for the electric potential energy of the system.
Here,
Conclusion:
Substitute
Thus, the electric potential energy of the system is
(c)
Total energy of the system.
(c)
Answer to Problem 60PQ
The total energy of the system is
Explanation of Solution
Write an expression for the kinetic energy.
Here,
Write an expression for the total energy.
Here,
Conclusion:
Substitute
Substitute
Thus, the total energy of the system is
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Chapter 26 Solutions
Physics for Scientists and Engineers: Foundations and Connections
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- A charged particle is moved in a uniform electric field between two points, A and B, as depicted in Figure P26.65. Does the change in the electric potential or the change in the electric potential energy of the particle depend on the sign of the charged particle? Consider the movement of the particle from A to B, and vice versa, and determine the signs of the electric potential and the electric potential energy in each possible scenario.arrow_forward(a) Find the electric potential difference Ve required to stop an electron (called a stopping potential) moving with an initial speed of 2.85 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude of electric potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential. Vp/Ve.arrow_forwardOppositely charged parallel plates are separated by 5.33 mm. A potential difference of 600 V exists between the plates. (a) What is the magnitude of the electric field between the plates? (b) What is the magnitude of the force on an electron between the plates? (c) How much work must be done on the electron to move it to the negative plate if it is initially positioned 2.90 mm from the positive plate?arrow_forward
- The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50 104 V/m. (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be at zero volts. What is the potential 1.00 cm from that plate (and 3.00 cm from the other)?arrow_forwardGiven two particles with 2.00-C charges as shown in Figure P25.19 and a particle with charge q = 1.28 10-18 C at the origin, (a) what is the net force exerted by the two 2.00-C; charges on the charge q? (b) What is the electric field at the origin due to the two 2.00-C particles? (c) What is the electric potential at the origin due to the two 2.00-C particles?arrow_forward(a) Find the potential difference VB required to stop an electron (called a slopping potential) moving with an initial speed of 2.85 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential, Vp/Ve. The answer should be in terms of the proton mass mp and electron mass me.arrow_forward
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