Physics for Scientists and Engineers: Foundations and Connections
15th Edition
ISBN: 9781305289963
Author: Debora M. Katz
Publisher: Cengage Custom Learning
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Chapter 26, Problem 62PQ
To determine
Show that the electrostatic forces do not fail the two tests for a conservative force.
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Physics for Scientists and Engineers: Foundations and Connections
Ch. 26.2 - Complete the analogies by filling in the blanks,...Ch. 26.3 - Prob. 26.2CECh. 26.3 - A water molecule is made up of two hydrogen atoms...Ch. 26.4 - Match the topographical maps in Figure 26.15 with...Ch. 26.5 - Which term or phrase is a synonym for electric...Ch. 26.7 - If the contours in Figure 26.26 represent the...Ch. 26.9 - Prob. 26.7CECh. 26 - What does it mean when a force is negative? What...Ch. 26 - Review Return to Chapter 8 and the potential...Ch. 26 - Review A system consists of a planet and a star,...
Ch. 26 - Try to complete Table P26.4 from memory. If you...Ch. 26 - Try to complete Table P26.5 from memory. If you...Ch. 26 - Can you associate electric potential energy with...Ch. 26 - Consider the final arrangement of charged...Ch. 26 - Using the usual convention that the electric...Ch. 26 - FIGURE P26.8 A Find an expression for the electric...Ch. 26 - A hydrogen atom consists of an electron and a...Ch. 26 - What is the work that a generator must do to move...Ch. 26 - How far should a +3.0-C charged panicle be from a...Ch. 26 - A proton is fired from very far away directly at a...Ch. 26 - Four charged particles are at rest at the corners...Ch. 26 - FIGURE P26.14 Problems 14, 15, and 16. Four...Ch. 26 - Four charged particles are at rest at the corners...Ch. 26 - Eight identical charged particles with q = 1.00 nC...Ch. 26 - A conducting sphere with a radius of 0.25 m has a...Ch. 26 - The speed of an electron moving along the y axis...Ch. 26 - Figure P26.20 is a topographic map. a. Rank A, B,...Ch. 26 - At a point in space, the electric potential due to...Ch. 26 - Explain the difference between UE(r) = kQq/r and...Ch. 26 - Suppose a single electron moves through an...Ch. 26 - Two point charges, q1 = 2.0 C and q2 = 2.0 C, are...Ch. 26 - Separating the electron from the proton in a...Ch. 26 - Can a contour map help you visualize the electric...Ch. 26 - Prob. 27PQCh. 26 - Find the electric potential at the origin given...Ch. 26 - Prob. 29PQCh. 26 - Prob. 30PQCh. 26 - Prob. 31PQCh. 26 - Prob. 32PQCh. 26 - A source consists of three charged particles...Ch. 26 - Two identical metal balls of radii 2.50 cm are at...Ch. 26 - Figure P26.35 shows four particles with identical...Ch. 26 - Two charged particles with qA = 9.75 C and qB =...Ch. 26 - Two charged particles with q1 = 5.00 C and q2 =...Ch. 26 - Prob. 38PQCh. 26 - Prob. 39PQCh. 26 - A uniformly charged ring with total charge q =...Ch. 26 - A line of charge with uniform charge density lies...Ch. 26 - A line of charge with uniform charge density =...Ch. 26 - A Consider a thin rod of total charge Q and length...Ch. 26 - Figure P26.44 shows a rod of length = 1.00 m...Ch. 26 - The charge density on a disk of radius R = 12.0 cm...Ch. 26 - Prob. 46PQCh. 26 - In some region of space, the electric field is...Ch. 26 - A particle with charge 1.60 1019 C enters midway...Ch. 26 - Prob. 49PQCh. 26 - Prob. 50PQCh. 26 - Prob. 51PQCh. 26 - Prob. 52PQCh. 26 - Prob. 53PQCh. 26 - According to Problem 43, the electric potential at...Ch. 26 - The electric potential is given by V = 4x2z + 2xy2...Ch. 26 - The electric potential V(x, y, z) in a region of...Ch. 26 - Prob. 57PQCh. 26 - In three regions of space, the electric potential...Ch. 26 - Prob. 59PQCh. 26 - Prob. 60PQCh. 26 - The distance between two small charged spheres...Ch. 26 - Prob. 62PQCh. 26 - A glass sphere with radius 4.00 mm, mass 85.0 g,...Ch. 26 - Prob. 64PQCh. 26 - Two 5.00-nC charged particles are in a uniform...Ch. 26 - A 5.00-nC charged particle is at point B in a...Ch. 26 - A charged particle is moved in a uniform electric...Ch. 26 - Figure P26.68 shows three small spheres with...Ch. 26 - What is the work required to charge a spherical...Ch. 26 - For a system consisting of two identical...Ch. 26 - Figure P26.71 shows three charged particles...Ch. 26 - Problems 72, 73, and 74 are grouped. 72. A Figure...Ch. 26 - A Start with V=2k[(R2+x2)x] for the electric...Ch. 26 - A Review Consider the charged disks in Problem 72...Ch. 26 - A long thin wire is used in laser printers to...Ch. 26 - An electric potential exists in a region of space...Ch. 26 - A disk with a nonuniform charge density =ar2 has...Ch. 26 - An infinite number of charges with q = 2.0 C are...Ch. 26 - An infinite number of charges with |q| =2.0 C are...Ch. 26 - Figure P26.80 shows a wire with uniform charge per...Ch. 26 - Prob. 81PQ
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- A helicopter rescues a trapped person of mass m = 65.0 kg from a flooded river by lifting the person vertically upward using a winch and rope. The person is pulled 12.0 m into the helicopter with a constant force that is 15% greater than the persons weight. a. Find the work done by each of the forces acting on the person. b. Assuming the survivor starts from rest, determine his speed upon reaching the helicopter.arrow_forwardIn three cases, a force acts on a particle, and the particle is displaced from an initial position to a final position. Figure 9.11 (page 255) shows the position-versus-force graphs, indicating the initial and final positions of the particle in each case. Find the work done by the force on the particle and sketch the force and displacement vectors along with the appropriate axis in each case.arrow_forwardA constant force of magnitude 4.75 N is exerted on an object. The forces direction is 60.0 counterclockwise from the positive x axis in the xy plane, and the objects displacement is r=(4.22.1j+1.6k)m. Calculate the work done by this force.arrow_forward
- (a) How high a hill can a car coast up (engines disengaged) if work done by friction is negligible and its initial speed is 110 km/h? (b) if, in actuality, a 750-kg car with an initial speed of 110 km/h is observed to coast up a hill to a height 22.0 m above its starting point, how much thermal energy was generated by friction? (c) What is the average force of friction if the hill has a slope of 2.5 above the horizontal?arrow_forwardOn a movie set, an alien spacecraft is to be lifted to a height of 30.0 m for use in a scene. The 200.0-kg spacecraft is attached by ropes to a massless pulley on a crane, and four members of the films construction crew lift the prop at constant speed by delivering 185 W of power each. If 20.0% of the mechanical energy delivered to the pulley is lost to friction, what is the time interval required to lift the spacecraft to the specified height?arrow_forwardAt the start of a basketball game, a referee tosses a basketball straight into the air by giving it some initial speed. After being given that speed, the ball reaches a maximum height ymax above where it started. Using conservation of energy, find expressions for a. the balls initial speed in terms of the gravitational acceleration g and the maximum height ymax and b. the height of the ball when it has speed v in terms of its current height y, the gravitational acceleration g, and the maximum height ymax.arrow_forward
- Starting at rest, Tina slides down a frictionless waterslide with a horizontal section at the bottom that is 4.00 ft above the surface of the swimming pool and strikes the water a distance of 15.0 ft away from the end of the slide. Using conservation of energy, what is Tinas initial height on the waterslide?arrow_forwardA force acting on a particle moving in the xy plane is given by F=(2yi+x2j), where F is in newtons and x and y are in meters. The particle moves from the origin to a final position having coordinates x = 5.00 m and y = 5.00 m as shown in Figure P7.31. Calculate the work done by F on the particle as it moves along (a) the purple path, (b) the red path, and (c) the blue path, (d) Is F conservative or nonconservative? (e) Explain your answer to part (d). Figure P7.31arrow_forwardA particle moves in the xy plane (Fig. P9.30) from the origin to a point having coordinates x = 7.00 m and y = 4.00 m under the influence of a force given by F=3y2+x. a. What is the work done on the particle by the force F if it moves along path 1 (shown in red)? b. What is the work done on the particle by the force F if it moves along path 2 (shown in blue)? c. What is the work done on the particle by the force F if it moves along path 3 (shown in green)? d. Is the force F conservative or nonconservative? Explain. FIGURE P9.30 In each case, the work is found using the integral of Fdr along the path (Equation 9.21). W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz) (a) The work done along path 1, we first need to integrate along dr=dxi from (0,0) to (7,0) and then along dr=dyj from (7,0) to (7,4): W1=x=0;y=0x=7;y=0(3y2i+xj)(dxi)+x=7;y=0x=7;y=4(3y2i+xj)(dyj) Performing the dot products, we get W1=x=0;y=0x=7;y=03y2dx+x=7;y=0x=7;y=4xdy Along the first part of this path, y = 0 therefore the first integral equals zero. For the second integral, x is constant and can be pulled out of the integral, and we can evaluate dy. W1=0+x=7;y=0x=7;y=4xdy=xy|x=7;y=0x=7;y=4=28J (b) The work done along path 2 is along dr=dyj from (0,0) to (0,4) and then along dr=dxi from (0,4) to (7,4): W2=x=0;y=0x=0;y=4(3y2i+xj)(dyj)+x=0;y=4x=7;y=4(3y2i+xj)(dyi) Performing the dot product, we get: W2=x=0;y=0x=0;y=4xdy+x=0;y=4x=7;y=43y2dx Along the first part of this path, x = 0. Therefore, the first integral equals zero. For the second integral, y is constant and can be pulled out of the integral, and we can evaluate dx. W2=0+3y2x|x=0;y=4x=7;y=4=336J (c) To find the work along the third path, we first write the expression for the work integral. W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz)W=rtrf(3y2dx+xdy)(1) At first glance, this appears quite simple, but we cant integrate xdy=xy like we might have above because the value of x changes as we vary y (i.e., x is a function of y.) [In parts (a) and (b), on a straight horizontal or vertical line, only x or y changes]. One approach is to parameterize both x and y as a function of another variable, say t, and write each integral in terms of only x or y. Constraining dr to be along the desired line, we can relate dx and dy: tan=dydxdy=tandxanddx=dytan(2) Now, use equation (2) in (1) to express each integral in terms of only one variable. W=x=0;y=0x=7;y=43y2dx+x=0;y=0x=7;y=4xdyW=y=0y=43y2dytan+x=0x=7xtandx We can determine the tangent of the angle, which is constant (the angle is the angle of the line with respect to the horizontal). tan=4.007.00=0.570 Insert the value of the tangent and solve the integrals. W=30.570y33|y=0y=4+0.570x22|x=0x=7W=112+14=126J (d) Since the work done is not path-independent, this is non-conservative force. Figure P9.30ANSarrow_forward
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