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College Physics:
11th Edition
ISBN: 9781305965515
Author: SERWAY, Raymond A.
Publisher: Brooks/Cole Pub Co
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Chapter 27, Problem 5P
To determine
The peak wavelength for the Earth.
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Chapter 27 Solutions
College Physics:
Ch. 27.5 - Prob. 27.1QQCh. 27.5 - Prob. 27.2QQCh. 27.5 - Prob. 27.3QQCh. 27.6 - Prob. 27.4QQCh. 27.6 - Prob. 27.5QQCh. 27 - Prob. 1CQCh. 27 - Prob. 2CQCh. 27 - Prob. 3CQCh. 27 - Prob. 4CQCh. 27 - Prob. 5CQ
Ch. 27 - Prob. 6CQCh. 27 - Prob. 7CQCh. 27 - Prob. 8CQCh. 27 - Prob. 9CQCh. 27 - Prob. 10CQCh. 27 - Prob. 11CQCh. 27 - Prob. 12CQCh. 27 - Prob. 13CQCh. 27 - Prob. 14CQCh. 27 - Prob. 15CQCh. 27 - Prob. 16CQCh. 27 - Prob. 1PCh. 27 - Prob. 2PCh. 27 - Prob. 3PCh. 27 - Prob. 4PCh. 27 - Prob. 5PCh. 27 - Prob. 6PCh. 27 - Prob. 7PCh. 27 - Prob. 8PCh. 27 - Prob. 9PCh. 27 - Prob. 10PCh. 27 - Prob. 11PCh. 27 - Prob. 12PCh. 27 - Prob. 13PCh. 27 - Prob. 14PCh. 27 - Prob. 15PCh. 27 - Prob. 16PCh. 27 - Prob. 17PCh. 27 - Prob. 18PCh. 27 - Prob. 19PCh. 27 - Prob. 20PCh. 27 - Prob. 21PCh. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - Prob. 24PCh. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - Prob. 28PCh. 27 - Prob. 29PCh. 27 - Prob. 30PCh. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Prob. 34PCh. 27 - Prob. 35PCh. 27 - Prob. 36PCh. 27 - Prob. 37PCh. 27 - Prob. 38PCh. 27 - Prob. 39PCh. 27 - Prob. 40PCh. 27 - Prob. 41APCh. 27 - Prob. 42APCh. 27 - Prob. 43APCh. 27 - Prob. 44APCh. 27 - Prob. 45APCh. 27 - Prob. 46APCh. 27 - Prob. 47APCh. 27 - Prob. 48APCh. 27 - Prob. 49APCh. 27 - Prob. 50APCh. 27 - Prob. 51APCh. 27 - Prob. 52AP
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- Problem-1: An asteroid is hurtling toward earth at 150,000“. The temperature of the asteroid is about 100 K, meaning that its peak emission is 2 = 29 µm. The speed of light is c = 3E[8]. a) What is the wavelength of light that we receive from the asteroid? (Answer: 2.89855E[-05] m)arrow_forwardEarth's average surface temperature is about 287 K. Assuming Earth radiates as a blackbody, calculate Amax for the Earth.arrow_forwardThe radius of our sun is r = 6.96 × 108 m and its total power is 3.85 × 1026 W. The area of a sphere is A = 4πr2.a) Assuming that the surface of the Sun emits like a black body, calculate its surface temperatureb) Using the result of part (a), find λmax for the sun.arrow_forward
- The thermal (black-body) radiation from a star peaks at a wavelength of 300 nm. What is the surface temperature of the star in K?arrow_forwardQuestion A7 The intensity of the emitted radiation by a star is at a maximum at a wavelength of 78.9 nm. a) Calculate the surface temperature of the star. b) Calculate the ratio of the intensity radiated at 65.0 nm to the maximum intensity. Assume that the star radiates like an ideal blackbody.arrow_forwardAn infrared satellite measures outgoing radiation that leaves Earth's surface through an atmospheric window. The observed spectral irradiance at a wavelength of 10 μm is 2.199×107 W m-2 m-1. What is the temperature of the surface? Give your answer in K.arrow_forward
- A log in the fire is glowing red (λ = 629 nm). What is the temperature of the log, in kelvin?arrow_forwardThe power emitted by a blackbody is proportional to T^4. If the temperature of the blackbody goes from 3000K to 6000K, by how much (by what factor, 2, 3, 8, etc) does the power increase?arrow_forwardA blackbody (a hollow sphere whose inside is black) emits radiation when it is heated. The emittance (Mλ, W/m3), which is the power per unit area per wavelength, at a given temperature (T, K) and wavelength (λ, m) is given by the Planck distribution, where h is Planck's constant, c is the speed of light, and k is Boltzmann's constant. Determine the temperature in degrees Celsius at which a blackbody will emit light of wavelength 3.57 μm with an Mλ of 5.31×1010 W/m3. The power per unit area emitted can be determined by integrating Mλ between two wavelengths, λ1 and λ2. However, for narrow wavelength ranges (Δλ), the power emitted can be simply calculated as the product of Mλ and Δλ. power emitted=MλΔλ Using the conditions from the first part of the question, determine the power emitted per square meter (W/m2) between the wavelengths 3.56 μm and 3.58 μm.arrow_forward
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