College Physics, Volume 1
11th Edition
ISBN: 9781337653329
Author: Raymond A. Serway; Chris Vuille
Publisher: Cengage Learning US
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Chapter 27, Problem 5P
To determine
The peak wavelength for the Earth.
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Earth's average surface temperature is about 287 K. Assuming
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The radius of our sun is r = 6.96 × 108 m and its total power is 3.85 × 1026 W. The area of a sphere is A = 4πr2.a) Assuming that the surface of the Sun emits like a black body, calculate its surface temperatureb) Using the result of part (a), find λmax for the sun.
Chapter 27 Solutions
College Physics, Volume 1
Ch. 27.5 - Prob. 27.1QQCh. 27.5 - Prob. 27.2QQCh. 27.5 - Prob. 27.3QQCh. 27.6 - Prob. 27.4QQCh. 27.6 - Prob. 27.5QQCh. 27 - Prob. 1CQCh. 27 - Prob. 2CQCh. 27 - Prob. 3CQCh. 27 - Prob. 4CQCh. 27 - Prob. 5CQ
Ch. 27 - Prob. 6CQCh. 27 - Prob. 7CQCh. 27 - Prob. 8CQCh. 27 - Prob. 9CQCh. 27 - Prob. 10CQCh. 27 - Prob. 11CQCh. 27 - Prob. 12CQCh. 27 - Prob. 13CQCh. 27 - Prob. 14CQCh. 27 - Prob. 15CQCh. 27 - Prob. 16CQCh. 27 - Prob. 1PCh. 27 - Prob. 2PCh. 27 - Prob. 3PCh. 27 - Prob. 4PCh. 27 - Prob. 5PCh. 27 - Prob. 6PCh. 27 - Prob. 7PCh. 27 - Prob. 8PCh. 27 - Prob. 9PCh. 27 - Prob. 10PCh. 27 - Prob. 11PCh. 27 - Prob. 12PCh. 27 - Prob. 13PCh. 27 - Prob. 14PCh. 27 - Prob. 15PCh. 27 - Prob. 16PCh. 27 - Prob. 17PCh. 27 - Prob. 18PCh. 27 - Prob. 19PCh. 27 - Prob. 20PCh. 27 - Prob. 21PCh. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - Prob. 24PCh. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - Prob. 28PCh. 27 - Prob. 29PCh. 27 - Prob. 30PCh. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Prob. 34PCh. 27 - Prob. 35PCh. 27 - Prob. 36PCh. 27 - Prob. 37PCh. 27 - Prob. 38PCh. 27 - Prob. 39PCh. 27 - Prob. 40PCh. 27 - Prob. 41APCh. 27 - Prob. 42APCh. 27 - Prob. 43APCh. 27 - Prob. 44APCh. 27 - Prob. 45APCh. 27 - Prob. 46APCh. 27 - Prob. 47APCh. 27 - Prob. 48APCh. 27 - Prob. 49APCh. 27 - Prob. 50APCh. 27 - Prob. 51APCh. 27 - Prob. 52AP
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- The blackbody radiation emitted from a furnace peaks at a wavelength of 2.5 10-6 m (0.0000025 m). What is the temperature inside the furnace? answer ... Karrow_forwardProblem-1: An asteroid is hurtling toward earth at 150,000“. The temperature of the asteroid is about 100 K, meaning that its peak emission is 2 = 29 µm. The speed of light is c = 3E[8]. a) What is the wavelength of light that we receive from the asteroid? (Answer: 2.89855E[-05] m)arrow_forwardThe thermal (black-body) radiation from a star peaks at a wavelength of 300 nm. What is the surface temperature of the star in K?arrow_forward
- Question A7 The intensity of the emitted radiation by a star is at a maximum at a wavelength of 78.9 nm. a) Calculate the surface temperature of the star. b) Calculate the ratio of the intensity radiated at 65.0 nm to the maximum intensity. Assume that the star radiates like an ideal blackbody.arrow_forwardAn infrared satellite measures outgoing radiation that leaves Earth's surface through an atmospheric window. The observed spectral irradiance at a wavelength of 10 μm is 2.199×107 W m-2 m-1. What is the temperature of the surface? Give your answer in K.arrow_forwardA log in the fire is glowing red (λ = 629 nm). What is the temperature of the log, in kelvin?arrow_forward
- The power emitted by a blackbody is proportional to T^4. If the temperature of the blackbody goes from 3000K to 6000K, by how much (by what factor, 2, 3, 8, etc) does the power increase?arrow_forwardQl: A nuclear bomb at the instant of explosion may be approximated to a blackbody of radius 1.3 m with a surface temperature of 107 K. find the bomb emits power ?arrow_forwardA blackbody (a hollow sphere whose inside is black) emits radiation when it is heated. The emittance (Mλ, W/m3), which is the power per unit area per wavelength, at a given temperature (T, K) and wavelength (λ, m) is given by the Planck distribution, where h is Planck's constant, c is the speed of light, and k is Boltzmann's constant. Determine the temperature in degrees Celsius at which a blackbody will emit light of wavelength 3.57 μm with an Mλ of 5.31×1010 W/m3. The power per unit area emitted can be determined by integrating Mλ between two wavelengths, λ1 and λ2. However, for narrow wavelength ranges (Δλ), the power emitted can be simply calculated as the product of Mλ and Δλ. power emitted=MλΔλ Using the conditions from the first part of the question, determine the power emitted per square meter (W/m2) between the wavelengths 3.56 μm and 3.58 μm.arrow_forward
- The intensity of blackbody radiation peaks at a wavelength of 513 nm. Determine the power radiated per unit area (in W/m2) of the radiation source at this temperature.arrow_forwardA blackbody has a temperature of 5 K. At what wave-length is it brightest?arrow_forwardThe wavelength of maximum solar emission is observed to be approximately 0.475 μm. What is the surface temperature of the sun (assumed as blackbody)?arrow_forward
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