Tutorials in Introductory Physics
Tutorials in Introductory Physics
1st Edition
ISBN: 9780130970695
Author: Peter S. Shaffer, Lillian C. McDermott
Publisher: Addison Wesley
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Chapter 27.2, Problem 3dTH
To determine

The total work done.

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I only need help with Part (d). Problem 1:   In this problem a heat engine, each cycle, absorbs an amount of energy Qh = 1915 J from a hot reservoir and expels an amount Qc = 1325 J into a cold reservoir. Each cycle lasts for a time of t = 0.34 seconds. Part (a)  Find the efficiency of an ideal engine operating between these reservoirs. Remember the efficiency is unit-less, therefore so should your number be as well.  eideal = 0.308   Part (b)  How much work, in Joules, is done per cycle at this efficiency?  Wideal = 590 Part (c)  How much power, in Watts, does the engine output per cycle at this efficiency?  P = 1735.29 Part (d)  What if the actual work done (more realistically) is W = 320 J during a single cycle; what is the efficiency of this engine if the energy input is the same (again, the number should be unit-less)?
Answer the following questions: a.How will you explain the first law of thermodynamics? Give a specific example. b.What law explains the mechanism of heat engines? Support your answer. c. Why do machines are not 100% efficient?
Please help me with these questions  a. What is the name given to this cycle, and why is it important? The volume of the ideal gas at point 1 is V1, etc. By analysing the adiabatic processes, we find that: V_2/V_1 = V_4/V_3 b. The work done during the isothermal processes is WC (between points 1 and 2) and WH (between points 3 and 4). Find an expression for the fraction WC / WH in terms of TC and TH. c. Apply the First Law of Thermodynamics to the isothermal processes to show that the efficiency of this cycle is (please see the image with the corresponding formula for question c) d. Use the Second Law of Thermodynamics to explain why no heat engine can be more efficient than a perfectly reversible engine. You may wish to include a heat flow diagram in your answer.
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