EBK COLLEGE PHYSICS, VOLUME 2
11th Edition
ISBN: 8220103599924
Author: Vuille
Publisher: CENGAGE L
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 27.6, Problem 27.5QQ
To determine
If the de Broglie wavelength of a nonrelativistic electron and a nonrelativistic proton are the same, which of the given quantities are the same for the two particles.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
A quantum particle of mass m is placed in a one-dimensional box of length L. Assume the box is so small that the particle’s motion is relativistic and K = p2/2m is not valid. (a) Derive an expression for the kinetic energy levels of theparticle. (b) Assume the particle is an electron in a box of length L = 1.00 × 10-12 m. Find its lowest possible kinetic energy. (c) By what percent is the nonrelativistic equation in error?
A particle has a de Broglie wavelength of 2.80×10−102.80×10−10 m. Then its kinetic energy doubles. What is the particle's new de Broglie wavelength, assuming that relativistic effects can be ignored?
A proton in a linear accelerator has a de Broglie wavelength of 117 pm. What is the speed of the proton? Express your answer with the appropriate units.
Chapter 27 Solutions
EBK COLLEGE PHYSICS, VOLUME 2
Ch. 27.5 - Prob. 27.1QQCh. 27.5 - Prob. 27.2QQCh. 27.5 - Prob. 27.3QQCh. 27.6 - Prob. 27.4QQCh. 27.6 - Prob. 27.5QQCh. 27 - Prob. 1CQCh. 27 - Prob. 2CQCh. 27 - Prob. 3CQCh. 27 - Prob. 4CQCh. 27 - Prob. 5CQ
Ch. 27 - Prob. 6CQCh. 27 - Prob. 7CQCh. 27 - Prob. 8CQCh. 27 - Prob. 9CQCh. 27 - Prob. 10CQCh. 27 - Prob. 11CQCh. 27 - Prob. 12CQCh. 27 - Prob. 13CQCh. 27 - Prob. 14CQCh. 27 - Prob. 15CQCh. 27 - Prob. 16CQCh. 27 - Prob. 1PCh. 27 - Prob. 2PCh. 27 - Prob. 3PCh. 27 - Prob. 4PCh. 27 - Prob. 5PCh. 27 - Prob. 6PCh. 27 - Prob. 7PCh. 27 - Prob. 8PCh. 27 - Prob. 9PCh. 27 - Prob. 10PCh. 27 - Prob. 11PCh. 27 - Prob. 12PCh. 27 - Prob. 13PCh. 27 - Prob. 14PCh. 27 - Prob. 15PCh. 27 - Prob. 16PCh. 27 - Prob. 17PCh. 27 - Prob. 18PCh. 27 - Prob. 19PCh. 27 - Prob. 20PCh. 27 - Prob. 21PCh. 27 - Prob. 22PCh. 27 - Prob. 23PCh. 27 - Prob. 24PCh. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Prob. 27PCh. 27 - Prob. 28PCh. 27 - Prob. 29PCh. 27 - Prob. 30PCh. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Prob. 34PCh. 27 - Prob. 35PCh. 27 - Prob. 36PCh. 27 - Prob. 37PCh. 27 - Prob. 38PCh. 27 - Prob. 39PCh. 27 - Prob. 40PCh. 27 - Prob. 41APCh. 27 - Prob. 42APCh. 27 - Prob. 43APCh. 27 - Prob. 44APCh. 27 - Prob. 45APCh. 27 - Prob. 46APCh. 27 - Prob. 47APCh. 27 - Prob. 48APCh. 27 - Prob. 49APCh. 27 - Prob. 50APCh. 27 - Prob. 51APCh. 27 - Prob. 52AP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- a. The kinetic energy of an electron is (? + 1.5)keV. Find the de Broglie wavelength and momentum of the electron.arrow_forwardWhat is the(a) momentum,(b) speed, and(c) de Broglie wavelength of an electron with kinetic energy of 120 eV.arrow_forwardIt is stated in the text that special relativity must be used to calculate the de Broglie wavelength of electrons in an electron microscope. Let us discover how much of an effect relativity has. Consider an electron accelerated through a potential difference of 1.00 x 105 V.a. Using the Newtonian (nonrelativistic) expressions for kinetic energy and momentum, what is the electron’s de Broglie wavelength?b. The de Broglie wavelength is λ = h/p, but the momentum of a relativistic particle is not mv. Using the relativistic expressions for kinetic energy and momentum, what is the electron’s de Broglie wavelength?arrow_forward
- An electron is accelerated from rest through a potential difference of 3.19 x 102 V. Determine the following for the electron. (a) speed (ignore relativistic effects) m/s (b) de Broglie wavelength marrow_forwardwhat is the speed of an electron that has the same momentum as a photon with a wavelength in vacuum of 488 nm? The mass of an electron is 9.11 × 10^–31 kg.arrow_forwardAn electron, an α-particle, and a proton have the same kinetic energy. Which of these particles has the shortest de Broglie wavelength?arrow_forward
- A particle has a de Broglie wavelength of 3.0 × 10-10m. Then its kinetic energy increases by a factor of 4. What is the particle's new de Broglie wavelength, assuming that relativistic effects can be ignored? Number i Unitsarrow_forwardWhen developing a night vision night vision equipment, you need to measure the work function for the surface of a metal, so you perform a photoelectric photoelectric effect experiment. You measure the cutoff potential V0 as a function of of the wavelength À of light striking the surface. The results appear in the following table. In your analysis, you use c = 2.998 X 10^8 m/s and e = 1.602 X 10^-19 C, which are values obtained in other experiments. (a) Select a way to represent your results graphicallyso that the data points are close to a straight line. Using this graph, find the slope and the intercept y of the straight line that best fits the data. (b) Use the results from (a) to calculate the Planck constant h (as a test of your data) and the work function ( in and V) of the surface. ( c) What is the longest wavelength of light that will produce photoelectrons from this surface? (d) What wavelength of wavelength of light is required to produce photoelectrons with a kinetic energy…arrow_forward1.4 A beam of x-rays with wavelength 0.2400 nm is directed towards a sample. The x-rays scatter from the electrons within the sample, imparting momentum to the electrons, which are initially at rest in the lab frame. After scattering, the x-rays are detected at various angles relative to the direction of the incoming beam using a detector that can resolve their wavelengths. What is the longest wavelength measured by the detector?arrow_forward
- You want to use a microscope to study the structure of a mitochondrion about 1.00 um in size. To be able to observe small details within the mitochondrion, you want to use a wavelength of 0.0500 nm. If your microscope uses light of this wavelength, what is the momentum p of a photon? p = kg-m/s If your microscope uses light of this wavelength, what is the energy E of a photon? E = If instead your microscope uses electrons of this de Broglie wavelength, what is the momentum p. of an electron? Pe = kg-m/s If instead your microscope uses electrons of this de Broglie wavelength, what is the velocity v of an electron? v = m/s If instead your microscope uses electrons of this de Broglie wavelength, what is the kinetic energy K of an electron? K = What advantage do your calculations suggest electrons have compared to photons? O An electron's charge allows it to attach to observed particles, whereas a photon's electric neutrality prevents it from moving close enough to the observed particles…arrow_forwardDe Broglie postulated that the relationship ? = h/p is valid for relativistic particles. What is the de Broglie wavelength for a (relativistic) electron having a kinetic energy of 3.31 MeV? answer in marrow_forwardAn electron in a piece of aluminum requires at least 6.73e-19 J of energy to be ejected from the aluminum. What wavelength of EM radiation does this correspond to? If instead the electron in Problem #6 is struck by EM radiation with a wavelength of 205 nm, how much kinetic energy will it have upon leaving the aluminum? What is the final speed of the electron in Problem #7?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning