Pearson eText for College Physics: Explore and Apply -- Instant Access (Pearson+)
2nd Edition
ISBN: 9780137443000
Author: Eugenia Etkina, Gorazd Planinsic
Publisher: PEARSON+
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Chapter 28, Problem 16CQ
To determine
The importance of studying atomic models that are not accurate.
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what would be the atomic number of an element that would result from beta particle emission from 46 35X?
46 is on top, 35 on bottom.
By READING the N vs t graph shown below, determine No & the half-life.
N (x10¹ atoms)
120
90.
60.
30.
1
2
3 4 5 6 7 8 9 10
t(y)
No =
half-life =
atoms
Choose the BEST answer to the following.
A certain element emits 1 alpha particle, and its products then emit 2 beta particles in succession. The atomic number of the resulting element is changed by
(a) zero.
(b) minus 1.
(c) minus 2.
(d) plus 1.
Chapter 28 Solutions
Pearson eText for College Physics: Explore and Apply -- Instant Access (Pearson+)
Ch. 28 - Prob. 1RQCh. 28 - Prob. 2RQCh. 28 - Prob. 3RQCh. 28 - Prob. 4RQCh. 28 - Prob. 5RQCh. 28 - Prob. 6RQCh. 28 - Prob. 7RQCh. 28 - Prob. 8RQCh. 28 - Prob. 1MCQCh. 28 - Prob. 2MCQ
Ch. 28 - Prob. 3MCQCh. 28 - Prob. 4MCQCh. 28 - Prob. 5MCQCh. 28 - Prob. 6MCQCh. 28 - Prob. 7MCQCh. 28 - Prob. 8MCQCh. 28 - Prob. 9MCQCh. 28 - Prob. 10MCQCh. 28 - Prob. 11MCQCh. 28 - Prob. 12MCQCh. 28 - Prob. 13CQCh. 28 - Prob. 14CQCh. 28 - Prob. 15CQCh. 28 - Prob. 16CQCh. 28 - Prob. 17CQCh. 28 - Prob. 18CQCh. 28 - Prob. 19CQCh. 28 - Prob. 20CQCh. 28 - Prob. 21CQCh. 28 - Prob. 22CQCh. 28 - Prob. 23CQCh. 28 - Prob. 24CQCh. 28 - Prob. 25CQCh. 28 - Prob. 26CQCh. 28 - Prob. 27CQCh. 28 - Prob. 28CQCh. 28 - Prob. 29CQCh. 28 - Prob. 30CQCh. 28 - Prob. 31CQCh. 28 - Prob. 32CQCh. 28 - Prob. 33CQCh. 28 - Prob. 34CQCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 5PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - 28.4 Lasers (a) A laser pulse emits 2.0 J of...Ch. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 28PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46PCh. 28 - Prob. 47PCh. 28 - Prob. 48PCh. 28 - Prob. 49PCh. 28 - Prob. 50PCh. 28 - Prob. 51PCh. 28 - Prob. 52PCh. 28 - Prob. 53PCh. 28 - Prob. 54PCh. 28 - Prob. 55PCh. 28 - Prob. 56PCh. 28 - Prob. 57PCh. 28 - Prob. 58PCh. 28 - Prob. 59GPCh. 28 - Prob. 60GPCh. 28 - Prob. 61GPCh. 28 - Prob. 62GPCh. 28 - Prob. 63GPCh. 28 - Prob. 64GPCh. 28 - Prob. 65GPCh. 28 - Prob. 66GPCh. 28 - Prob. 67GPCh. 28 - Prob. 68RPPCh. 28 - Prob. 69RPPCh. 28 - Prob. 70RPPCh. 28 - Prob. 71RPPCh. 28 - Prob. 72RPPCh. 28 - Prob. 73RPPCh. 28 - Prob. 74RPPCh. 28 - Prob. 75RPPCh. 28 - Prob. 76RPPCh. 28 - Prob. 77RPPCh. 28 - Prob. 78RPP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Silver has two stable isotopes. The nucleus, 47107Ag , has atomic mass 106.905095 g/mol with an abundance of 51.83% ; whereas 47107Aghas atomic mass 108.904754 g/mol with an abundance of 48.17% . Find the atomic mass of the element silver.arrow_forwardThe atomic weight of cadmium is 112.41, and its density is 8.65 g/cm3. Using Figure 14.3, estimate the attenuation distance of a thermal neutron beam in cadmium. (The attenuation distance is the distance traveled after which the intensity of the beam is reduced to 1/e of its initial value, where e is the base of the natural logarithms.)arrow_forwardData from the appendices and the periodic table may be needed for these problems. 44. An old camp?re is uncovered during an archaeological dig. Its charcoal is found to contain less than 1/1000 the normal amount of 14C. Estimate the minimum age at the charcoal, noting that 210 = 1024.arrow_forward
- Enter the correct nuclide symbol in each open tan rectangle in Figure P43.25, which shows the sequences of decays in the natural radioactive series starting with the long-lived isotope uranium-235 and ending with the stable nucleus lead-207. Figure P43.25arrow_forwardWhen a nucleus decays by emitting an alpha particle, what is the atomic number of the resulting nucleus? What is the resulting atomic mass?arrow_forwardIt is handy to have an equation to quickly determine the number of atoms left in a radioactive sample as a function of time. For this we can divide the initial amount by two for every half-life of time, the following equation does exactly that: No No 2 1/2 (21/2) where Nois the initial number of atoms at t=0, t is time passed and is the half-life. Use the above equation to help you answer the question below. Substance X has a half-life of 10 years, if you start with 1000 grams, how much will be left after 100 years? (Give your answer in units of grams)arrow_forward
- Choose the BEST answer to the following. When an element ejects a beta particle, the atomic number of that element (a) reduces by 1. (b) increases by 1. (c) reduces by 2. (d) increases by 2.arrow_forwardAn ancient building was known to have been built 3000 years ago. Approximately what proportion of Carbon-14 atoms are yet in the building's wooden framing compared to the number which were present at the time of its construction? (half life of 14C = 5730 years)arrow_forwardA radioactive material has a half life of 4.6 minutes. After 8.1 minutes, which percentage of the original number of atoms will be left in it? Keep three significant digits.arrow_forward
- 1 What is the atomic number for an element whose mass number is 92, which contains 52 neutrons per atom? 4 7 +/- 2 LO 5 Time's Up! 8 3 6 9 0 Submit Tap here or pull up for additional resources X C x 100arrow_forward18. DETAILS MY NOTES ASK YOUR TEACHER State the changes in the values of the mass number and the atomic number of an element, when it undergoes beta decay. O The mass number does not change and the atomic number decreases by 2. O The mass number does not change and the atomic number increases by 1. O The mass number decreases by 4 and the atomic number increases by 1. O The mass number increases by 2 and the atomic number increases by 1. 19. DETAILS MY NOTES ASK YOUR TEACHER The decay rate ON, for N number of radioactive nuclei is dt dN = -AN What is meant by higher decay constant A? O The half-life is longer. O The decay energy is lower. O The activity is lower. O The probability of decay per second is higher.arrow_forwardElements above uranium in the periodic table do not exist in any appreciable amounts in nature because they have short half-lives. Yet there are several elements below uranium in atomic number with equally short half-lives that do exist in appreciable amounts in nature. How can you account for this?arrow_forward
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