General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 28, Problem 31E
(a)
To determine
The value of the energy of the electron in
(b)
To determine
The value of
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Can nuclei of the same element have different values of Z? Of N? Of A? Can nuclei of different elements have the same values of Z? Of N? Of A?
The energies, ?, for the first few states of an unknown element are given in the table in arbitrary units.
n
1
2
3
4
...
∞
E
−11
−5
−2
−1
...
0
A gaseous sample of this element is bombarded by photons of various energies in these same units.
Match each photon to the result of its absorption, or lack thereof, by an ?=1 electron.
Photon
Energy
Result
A
11
?
B
9
?
C
8
?
D
6
?
In an hydrogen atom, the electron orbit radius in the n = 2 state is measured to be ra, and that in the n = 6 state is measured to be rb. What is the ratio of rb/ra (remember to use the scientific notation)?
Chapter 28 Solutions
General Physics, 2nd Edition
Ch. 28 - Prob. 1RQCh. 28 - Prob. 2RQCh. 28 - Prob. 3RQCh. 28 - Prob. 4RQCh. 28 - Prob. 5RQCh. 28 - Prob. 6RQCh. 28 - Prob. 7RQCh. 28 - Prob. 8RQCh. 28 - Prob. 9RQCh. 28 - Prob. 10RQ
Ch. 28 - Prob. 1ECh. 28 - Prob. 2ECh. 28 - Prob. 3ECh. 28 - Prob. 4ECh. 28 - Prob. 5ECh. 28 - Prob. 6ECh. 28 - Prob. 7ECh. 28 - Prob. 8ECh. 28 - Prob. 9ECh. 28 - Prob. 10ECh. 28 - Prob. 11ECh. 28 - Prob. 12ECh. 28 - Prob. 13ECh. 28 - Prob. 14ECh. 28 - Prob. 15ECh. 28 - Prob. 16ECh. 28 - Prob. 17ECh. 28 - Prob. 18ECh. 28 - Prob. 19ECh. 28 - Prob. 20ECh. 28 - Prob. 21ECh. 28 - Prob. 22ECh. 28 - Prob. 23ECh. 28 - Prob. 24ECh. 28 - Prob. 25ECh. 28 - Prob. 26ECh. 28 - Prob. 27ECh. 28 - Prob. 28ECh. 28 - Prob. 29ECh. 28 - Prob. 30ECh. 28 - Prob. 31ECh. 28 - Prob. 32ECh. 28 - Prob. 33ECh. 28 - Prob. 34ECh. 28 - Prob. 35ECh. 28 - Prob. 36ECh. 28 - Prob. 37ECh. 28 - Prob. 38ECh. 28 - Prob. 39ECh. 28 - Prob. 40ECh. 28 - Prob. 41ECh. 28 - Prob. 42ECh. 28 - Prob. 43ECh. 28 - Prob. 44ECh. 28 - Prob. 45ECh. 28 - Prob. 46ECh. 28 - Prob. 47ECh. 28 - Prob. 48ECh. 28 - Prob. 49ECh. 28 - Prob. 50ECh. 28 - Prob. 51ECh. 28 - Prob. 52ECh. 28 - Prob. 53ECh. 28 - Prob. 54E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- The x-ray spectrum is for 35.0 keV electrons striking a molybdenum (Z= 42) target. If you substitute a silver (Z = 47) target for the molybdenum target, will (a) lmin, (b) the wavelength for the Ka line, and (c) the wavelength for the Kb line increase, decrease, or remain unchanged?arrow_forwardUsing the Bohr formulas, estimate the average distance from the nucleus for an electron in the innermost (n = 1) orbit in uranium (Z = 92). What is its kinetic energy and potential energy? Approximately how much energy would be required to remove it? (if possible with equations and a diagram, thanks)arrow_forwardConsider the electron of a Li2+ ion that undergoes a transition from a higher energy state n to its adjacent lower energy state n – 1 (e.g. n = 2→1, 3→2, 4→3, etc) and emits a photon. Suppose the emitted photon is used to strike the surface of potassium, which has a threshold frequency of 5.464 × 10^14 s–1.a) Whatisthemaximuminitialquantumnumber,n, that is required in order to emit a photon with high enough energy to generate a photocurrent from the metal surface?b) Usingthenvaluesolvedinpart(a), calculate the maximum speed of the photoelectron from potassium. If you couldn’t solve for n in part (a), use n = 3.arrow_forward
- Wavelength of the Balmer series is emitted as the electron in the hydrogen atom falls from, according to the above figure) n = (3 to ∞) to n = 2. What would be the specific wavelength of such a line for ni = 4? [Hint :1/λ = RH(1/nf2 – 1/ni2), RH being Rydberg constant = 1.097 × 107 /m] Group of answer choices 562 nm 486 nm 1122 nm 780 nmarrow_forwardUsing the Bohr formula for the radius of an electron orbit,estimate the average distance from the nucleus for anelectron in the innermost n=1 orbit of a uranium atom(z=92)Approximately how much energy would berequired to remove this innermost electron?arrow_forwardif the energy levels for a hydrogenic atom are given by En=-13.6/n^2eV, the ionization energy of the U91+ ion in its ground state is: a) 13.6eV , b) 1,251.2eV, c) 1,237.6eV, d) 115,110.4eV, e) 112,621.6eVarrow_forward
- The energy difference between the two levels arising from the spin-orbit coupling in a d-orbital is 0.6463 eV. Consider the splitting for one electron. Calculate the spin-orbit coupling constant in cm-1. please show all calculations. What atom could that be? (Hint: calculate the spin-orbit coupling constant in Ry and look for a matching number in the last column that provides experimental values) constant : 1 eV = 1.60217646 × 10-19 J 1Ry = 2.1798741 × 10-18 Jarrow_forwardWhich of these expressions would yield the wavelength of light in meters emitted when an electron drops from orbit n = 3 to n = 2 in a Bohr hydrogen atom? Given h = 4.14 x 10-15 eVs and c = 3.00 x 108 m/s. a. 1.89/hxc b. hc/1.89 c. 1.89 x h x c d. (1.51 + 3.4)/hc e. hc/3.4arrow_forwardConsider the elements selenium (Z = 34), bromine (Z = 35), and krypton (Z = 36). In their part of the periodic table, the subshells of the electronic states are filled in the sequence 1s 2s 2p 3s 3p 3d 4s 4p . . . . What are (a) the highest occupied subshell for selenium and (b) the number of electrons in it, (c) the highest occupied subshell for bromine and (d) the number of electrons in it, and (e) the highest occupied subshell for krypton and (f) the number of electrons in it?arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage LearningPhysics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning