Glencoe Physics: Principles and Problems, Student Edition
Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN: 9780078807213
Author: Paul W. Zitzewitz
Publisher: Glencoe/McGraw-Hill
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Chapter 28, Problem 36A
To determine

To write: A physics problem with real-life objects for which the following equation would be a part of the solution:

  E=13.6 eV(112132)

Expert Solution & Answer
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Explanation of Solution

Introduction:

Energy of a hydrogen atom is given by,

  En=13.6 eV ×1n2

Where n is the principal quantum number.

A real problem for the given solution can be written as follows:

A hydrogen atom is at E3 energy level. How much energy would be released if the atom dropped down to E1 energy level.

Conclusion:

According to above written problem, Ef=E1 and Ei=E3 . On calculating the energy of the hydrogen atom at both the levels and then using the formula of energy transitions of an atom, the given solution is obtained.

  E=EfEi    =E1E3    =13.61213.632   =13.6 eV(112132)

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