Masteringphysics With Pearson Etext - Valuepack Access Card - For College Physics
10th Edition
ISBN: 9780321976932
Author: YOUNG
Publisher: PEARSON
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Question
Chapter 28, Problem 53GP
(a)
To determine
The least amount of energy that must be given to a hydrogen atom.
(b)
To determine
The number of possible lines and the wavelength for the for the transition starts from n=3 level and eventually ends up in the ground level.
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A Hydrogen atom initially in its ground state i.e., n = 1 level, absorbs a photon and ends up in n = 4 level. (a) What must have been the frequency of the photon? Now the electron makes spontaneous emission and comes back to the ground state. (b) What are the possible frequencies of the photons emitted during this process?
A triply ionised beryllium atom (Be+++, Z = 4) has only one electron in
orbit about the nucleus. If the electron decays from the n
7 level to the
first excited state (n = 2), calculate the wavelength of the photon emitted.
Please give your answer in units of nm, rounded to one decimal place.
Answer:
Singly ionized helium has a single orbiting electron, so the mathematicsof the Bohr hydrogen atom will apply, with one important difference: The charge of the nucleus is twice that of the single proton at the center of a hydrogen atom. This changes the energy levels; the magnitude of each energy is greater than the corresponding Bohr level by a factor of 22 = 4: The Balmer and Lyman series of spectral lines in hydrogen have analogs in singly ionized helium, but at shorter wavelengths; the photons corresponding to these transitions are beyond the visiblelight spectrum. The transitions that end on the n = 4 state produce a set of spectral lines called the Pickering series. The visible-light lines in this series were first seen in the light from certain hot stars, but some of the lines overlap the hydrogen Balmer series lines, so these lines were initially missed. This led to an initial mischaracterization of the source of the lines.
The longest wavelength in the hydrogen Balmer series…
Chapter 28 Solutions
Masteringphysics With Pearson Etext - Valuepack Access Card - For College Physics
Ch. 28 - Prob. 1CQCh. 28 - Prob. 2CQCh. 28 - Prob. 3CQCh. 28 - Prob. 4CQCh. 28 - Prob. 5CQCh. 28 - Prob. 6CQCh. 28 - Prob. 7CQCh. 28 - Prob. 8CQCh. 28 - Prob. 9CQCh. 28 - Prob. 10CQ
Ch. 28 - Prob. 11CQCh. 28 - Prob. 12CQCh. 28 - Prob. 1MCPCh. 28 - Prob. 2MCPCh. 28 - Prob. 3MCPCh. 28 - Prob. 4MCPCh. 28 - Prob. 5MCPCh. 28 - Prob. 6MCPCh. 28 - Prob. 7MCPCh. 28 - Prob. 8MCPCh. 28 - Prob. 9MCPCh. 28 - Prob. 10MCPCh. 28 - Prob. 11MCPCh. 28 - Prob. 12MCPCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 5PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - Prob. 23PCh. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 28PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46PCh. 28 - Prob. 47PCh. 28 - Prob. 48PCh. 28 - Prob. 49PCh. 28 - Prob. 50GPCh. 28 - Prob. 51GPCh. 28 - Prob. 52GPCh. 28 - Prob. 53GPCh. 28 - Prob. 54GPCh. 28 - Prob. 55GPCh. 28 - Prob. 56GPCh. 28 - Prob. 57GPCh. 28 - Prob. 58GPCh. 28 - Prob. 59GPCh. 28 - Prob. 61GPCh. 28 - Prob. 62GPCh. 28 - Prob. 63GPCh. 28 - Prob. 64GPCh. 28 - Prob. 65GPCh. 28 - Prob. 66PPCh. 28 - Prob. 67PPCh. 28 - Prob. 68PPCh. 28 - Prob. 69PPCh. 28 - Prob. 70PPCh. 28 - Prob. 71PPCh. 28 - Prob. 72PPCh. 28 - Prob. 73PPCh. 28 - Prob. 74PP
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- Singly ionized helium has a single orbiting electron, so the mathematicsof the Bohr hydrogen atom will apply, with one important difference: The charge of the nucleus is twice that of the single proton at the center of a hydrogen atom. This changes the energy levels; the magnitude of each energy is greater than the corresponding Bohr level by a factor of 22 = 4: The Balmer and Lyman series of spectral lines in hydrogen have analogs in singly ionized helium, but at shorter wavelengths; the photons corresponding to these transitions are beyond the visiblelight spectrum. The transitions that end on the n = 4 state produce a set of spectral lines called the Pickering series. The visible-light lines in this series were first seen in the light from certain hot stars, but some of the lines overlap the hydrogen Balmer series lines, so these lines were initially missed. This led to an initial mischaracterization of the source of the lines. The Paschen series of wavelengths in the hydrogen…arrow_forwardSingly ionized helium has a single orbiting electron, so the mathematicsof the Bohr hydrogen atom will apply, with one important difference: The charge of the nucleus is twice that of the single proton at the center of a hydrogen atom. This changes the energy levels; the magnitude of each energy is greater than the corresponding Bohr level by a factor of 22 = 4: The Balmer and Lyman series of spectral lines in hydrogen have analogs in singly ionized helium, but at shorter wavelengths; the photons corresponding to these transitions are beyond the visiblelight spectrum. The transitions that end on the n = 4 state produce a set of spectral lines called the Pickering series. The visible-light lines in this series were first seen in the light from certain hot stars, but some of the lines overlap the hydrogen Balmer series lines, so these lines were initially missed. This led to an initial mischaracterization of the source of the lines. What energy is required to remove the remaining…arrow_forwardSingly ionized helium has a single orbiting electron, so the mathematicsof the Bohr hydrogen atom will apply, with one important difference: The charge of the nucleus is twice that of the single proton at the center of a hydrogen atom. This changes the energy levels; the magnitude of each energy is greater than the corresponding Bohr level by a factor of 22 = 4: The Balmer and Lyman series of spectral lines in hydrogen have analogs in singly ionized helium, but at shorter wavelengths; the photons corresponding to these transitions are beyond the visiblelight spectrum. The transitions that end on the n = 4 state produce a set of spectral lines called the Pickering series. The visible-light lines in this series were first seen in the light from certain hot stars, but some of the lines overlap the hydrogen Balmer series lines, so these lines were initially missed. This led to an initial mischaracterization of the source of the lines. What is, approximately, the longest wavelength that…arrow_forward
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