Masteringphysics With Pearson Etext - Valuepack Access Card - For College Physics
10th Edition
ISBN: 9780321976932
Author: YOUNG
Publisher: PEARSON
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Chapter 28, Problem 6CQ
To determine
The reason why the ultraviolet
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For years, exposure to ultra-violet radiation from prolonged time in the sun has been the major
identified cause of skin cancer. New research is showing that ultra-violet is not the only type of
radiation from the sun that can increase the risk of skin cancer. Rates of skin cancer among
pilots are twice that of non-pilots, but the glass used in planes blocks most the ultra-violet
radiation. Pilots are also exposed to x-rays from the sun during flight. The x-rays that pilots are
exposed to in one day of work are equivalent to a chest x-ray. Although getting an x-ray for
medical reasons is believed to be safe, researchers believe that the frequent exposer that pilots
experience increases their risk for skin cancer.
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My question is:
What is the frequency and wavelength of a 50 meV gamma-ray photon?
How do I find it?
The eyes of some birds contain cells that detect ultraviolet (UV) light.UV light is reflected by some fruits and the urine of small mammals.Explain how birds that detect UV light have evolved from birds that could not detect UV light?
This was a past GCSE paper question. I have already answered the quesiton as practice, but I can't find the mark scheme. Could you provide an answer which I can then use to check if my answer was correct?
Chapter 28 Solutions
Masteringphysics With Pearson Etext - Valuepack Access Card - For College Physics
Ch. 28 - Prob. 1CQCh. 28 - Prob. 2CQCh. 28 - Prob. 3CQCh. 28 - Prob. 4CQCh. 28 - Prob. 5CQCh. 28 - Prob. 6CQCh. 28 - Prob. 7CQCh. 28 - Prob. 8CQCh. 28 - Prob. 9CQCh. 28 - Prob. 10CQ
Ch. 28 - Prob. 11CQCh. 28 - Prob. 12CQCh. 28 - Prob. 1MCPCh. 28 - Prob. 2MCPCh. 28 - Prob. 3MCPCh. 28 - Prob. 4MCPCh. 28 - Prob. 5MCPCh. 28 - Prob. 6MCPCh. 28 - Prob. 7MCPCh. 28 - Prob. 8MCPCh. 28 - Prob. 9MCPCh. 28 - Prob. 10MCPCh. 28 - Prob. 11MCPCh. 28 - Prob. 12MCPCh. 28 - Prob. 1PCh. 28 - Prob. 2PCh. 28 - Prob. 3PCh. 28 - Prob. 4PCh. 28 - Prob. 5PCh. 28 - Prob. 6PCh. 28 - Prob. 7PCh. 28 - Prob. 8PCh. 28 - Prob. 9PCh. 28 - Prob. 10PCh. 28 - Prob. 11PCh. 28 - Prob. 12PCh. 28 - Prob. 13PCh. 28 - Prob. 14PCh. 28 - Prob. 15PCh. 28 - Prob. 16PCh. 28 - Prob. 17PCh. 28 - Prob. 18PCh. 28 - Prob. 19PCh. 28 - Prob. 20PCh. 28 - Prob. 21PCh. 28 - Prob. 22PCh. 28 - Prob. 23PCh. 28 - Prob. 24PCh. 28 - Prob. 25PCh. 28 - Prob. 26PCh. 28 - Prob. 27PCh. 28 - Prob. 28PCh. 28 - Prob. 29PCh. 28 - Prob. 30PCh. 28 - Prob. 31PCh. 28 - Prob. 32PCh. 28 - Prob. 33PCh. 28 - Prob. 34PCh. 28 - Prob. 35PCh. 28 - Prob. 36PCh. 28 - Prob. 37PCh. 28 - Prob. 38PCh. 28 - Prob. 39PCh. 28 - Prob. 40PCh. 28 - Prob. 41PCh. 28 - Prob. 42PCh. 28 - Prob. 43PCh. 28 - Prob. 44PCh. 28 - Prob. 45PCh. 28 - Prob. 46PCh. 28 - Prob. 47PCh. 28 - Prob. 48PCh. 28 - Prob. 49PCh. 28 - Prob. 50GPCh. 28 - Prob. 51GPCh. 28 - Prob. 52GPCh. 28 - Prob. 53GPCh. 28 - Prob. 54GPCh. 28 - Prob. 55GPCh. 28 - Prob. 56GPCh. 28 - Prob. 57GPCh. 28 - Prob. 58GPCh. 28 - Prob. 59GPCh. 28 - Prob. 61GPCh. 28 - Prob. 62GPCh. 28 - Prob. 63GPCh. 28 - Prob. 64GPCh. 28 - Prob. 65GPCh. 28 - Prob. 66PPCh. 28 - Prob. 67PPCh. 28 - Prob. 68PPCh. 28 - Prob. 69PPCh. 28 - Prob. 70PPCh. 28 - Prob. 71PPCh. 28 - Prob. 72PPCh. 28 - Prob. 73PPCh. 28 - Prob. 74PP
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- Ultraviolet (UV) radiation is a part of the electromagnetic spectrum that reaches the Earth from the Sun. It has wave-lengths shorter than those of visible light, making it invisible to the naked eye. These wavelengths are classified as UVA, UVB, or UVC, with UVA the longest of the three at 320 nm to 400 nm. Both the U.S. Department of Health and Human Services and the World Health Organization have identified UV as a proven human carcinogen. Many experts believe that, especially for fair-skinned people, UV radiation frequently plays a key role in melanoma, the deadliest form of skin cancer, which kills more than 8000 Americans each year. UVB has a wave-length between 280 nm and 320 nm. Determine the frequency ranges of UVA and UVB.arrow_forwardSuppose that the microwave radiation has a wavelength of 11.6 cm. How many photons are required to heat 265 mL of coffee from 25.0 degrees Celcius to 62.0 degrees Celcius? Assume that the coffee has the same density, 0.997 g/mL, and specific heat capacity, 4.184 J/(g.K), as water over this temperature range.arrow_forwardThe threshold of dark-adapted (scotopic) vision is 4.5 ✕ 10−11 W/m2 at a central wavelength of 500 nm. If light with this intensity and wavelength enters the eye when the pupil is open to its maximum diameter of 7.9 mm, how many photons per second enter the eye? photons/sarrow_forward
- The intensity of the sunlight reaching the Earth's surface is 1268 W/m2 and the average wavelength of the sunlight is 550 nm. (A) Energy of each photon = (B) Number of photons in the sunlight reaching the Earth's surface per square meter per second = (C) Energy deposited on a solar-panel of size 3.4 m x 2 m per second = (D) Energy converted to electricity per second by this solar-panel if its efficiency is 27.4% =arrow_forwardWhen photons pass through matter, the intensity I of the beam (measured in watts per square meter) decreases exponentially according to I = I0e-μxwhere I is the intensity of the beam that just passed through a thickness x of material and I0 is the intensity of the incident beam. The constant μ is known as the linear absorption coefficient, and its value depends on the absorbing material and the wavelength of the photon beam. This wavelength (or energy) dependence allows us to filter out unwanted wavelengths from a broad-spectrum x-ray beam.(a) Two x-ray beams of wavelengths λ1 and λ2 and equal incident intensities pass through the same metal plate. Show that the ratio of the emergent beam intensities is (I2)/(I1) = e-(μ2 - μ1)x(b) Compute the ratio of intensities emerging from an aluminum plate 1.00 mm thick if the incident beam contains equal intensities of 50 pm and 100 pm x-rays. The values of μ for…arrow_forwardThe threshold of dark-adapted (scotopic) vision is 4.5 ✕ 10−11 W/m2 at a central wavelength of 500 nm. If light with this intensity and wavelength enters the eye when the pupil is open to its maximum diameter of 7.9 mm, how many photons per second enter the eye?arrow_forward
- The threshold of dark - adapted (scotopic) vision is 4.0 x 10-11 W/m2 at a central wavelength of 5.00 x 102 nm. If light with this intensity and wavelength enters the eye when the pupil is open to its maximum diameter of 8.5 mm, how many photons per second enter the eye?arrow_forwardWater is exposed to infrared radiation of wavelength 2.8x10^-4 cm. Assume that all the radiation is absorbed and converted to heat. How many photons are required for the sample to absorb 16.72 J of heat?arrow_forwardThe average threshold of dark-adapted (scotopic) vision is 4.00 x 10-11 W/m2 at a central wavelength of 500 nm. If light with this intensity and wavelength enters the eye and the pupil is open to its maximum diameter of 7.00 mm, how many photons per second enter the eye?arrow_forward
- Suppose an infrared photon has a frequency of 2.2 × 1013 Hz. Part (a) Calculate the energy, in electron volt, of the infrared photon. Part (b) How many of these photons would need to be absorbed simultaneously by a molecule with binding energy 10.0 eV to break it apart? Part (c) What is the energy, in electron volts, of a γ-ray of frequency 2.95 × 1020 Hz? Part (d) What is the largest number of the molecules from part (b) that a single such γ-ray could break apart?arrow_forwardSuppose an infrared photon has a frequency of 1.9x1013 Hz. a) How many of these photons would need to be absorbed simultaneously by a molecule with a binding energy of 10.0 eV to break it apart? b) What is the energy, in eV of a y-ray of frequency 2.95 x 1020 Hz? c) What is the largest number of molecules from part (a) that a single such y-ray could break apart?arrow_forwardCalculate the thickness of aluminium foil that is needed to stop the electrons with an energy of 9 joules, knowing that the density of aluminium is 2.7 kg/m^3arrow_forward
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