Physics for Scientists and Engineers with Modern Physics, Technology Update
9th Edition
ISBN: 9781305401969
Author: SERWAY, Raymond A.; Jewett, John W.
Publisher: Cengage Learning
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Question
Chapter 28, Problem 75AP
(a)
To determine
The steady state current in each resistor.
(b)
To determine
The maximum charge on the capacitor.
(c)
To determine
The equation for the current in the resistor
(d)
To determine
The time interval for the charge to fall to one fifth its initial value.
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A 2.00-nF capacitor with an initial charge of 5.38 µC is discharged through a 1.34-k2 resistor.
(a) Calculate the magnitude of the current in the resistor 9.00 us after the resistor is connected across the terminals of the capacitor.
(b) What charge remains on the capacitor after 8.00 us?
µC
(c) What is the maximum current in the resistor?
A
In Figure P28.67, suppose the switch has been closed for a length of time sufficiently long for the capacitor to become fully charged. (E = 8.50 V, r1 = 10 kN, and r2 = 16 kN.)
10.0 µF
3.00 k2
Figure P28.67
(a) Find the steady-state current in each resistor.
I = 327
HA
I2 = 327
HA
13-kn = 0
HA
(b) Find the charge Q on the capacitor.
52
(c) The switch is opened at t = 0. Write an equation for the current IR, in R2 as a function of time.
O (327 HA)e-t/(0.190 s)
O (275 µA)et/(0.190 s)
O (275 µA)e-t/(0.190 s)
O (327 µA)et/(0.190 s)
(d) Find the time that it takes for the charge on the capacitor to fall to one-fifth its initial value.
ms
In Figure P28.67, suppose the switch has been closed for a length of time sufficiently long for the capacitor to become fully charged. (E = 8.50 V, r1 = 10 kN, and r2 = 16 kN.)
10.0 µF
3.00 k2
Figure P28.67
(a) Find the steady-state current in each resistor.
I1 = 1.32
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. µA
I2 = 4.32
Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. µA
I3-ko = 0
HA
(b) Find the charge Q on the capacitor.
8.83
Your response differs from the correct answer by more than 10%. Double check your calculations. µC
(c) The switch is opened at t = 0. Write an equation for the current IR, in R, as a function of time.
O (327 µA)e-t/(0.190 s)
O (275 µA)et/(0.190 s)
O (275 µA)e-t/(0.190 s)
O (327 µA)et/(0.190 s)
(d) Find the time that it takes for the charge on the capacitor to fall to one-fifth its initial…
Chapter 28 Solutions
Physics for Scientists and Engineers with Modern Physics, Technology Update
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