Explanation Given data: Kinetic energy of the emitted electrons is 1.50eV. Wavelength of light is 250 nm. Formula used: Consider the work function equation. E = h c λ (1) Here, h is the planks constant, which has a standard value as 6.63 × 10 − 34 J ⋅ s , c is the speed of light , which has a standard value as 3 × 10 8 m s , and λ is the wavelength. Explanation: Substitute 6.63 × 10 − 34 J ⋅ s for h , 3 × 10 8 m s for c , and 250 nm for λ in equation (1), E = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 250nm = ( 6.63 × 10 − 34 J ⋅ s ) ( 3 × 10 8 m s ) 250 × 10 − 9 m = 0.0795 × 10 − 17 J Consider the conversion factor for J to eV

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Question

Chapter 28, Problem 9P

To determine

The maximum kinetic energy of the metal when illuminated by light with a wavelength of 250 nm.

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Chapter 28, Problem 8P

Chapter 28, Problem 10P

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A metal surface is illuminated by light with a wavelength of 350 nm. The maximum kinetic energy of the emitted electrons is found to be 1.50 eV. What is the maximum electron kinetic energy if the same metal is illuminated by light with a wavelength of 250 nm?

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Chapter 28 Solutions

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