a. Explanation Formula used: Consider the following expression. 1 m 2 − 1 n 2 = 91.1 nm λ (1) Here, m is the final electron’s orbit, n is the initial electron’s orbit, and λ is the wavelength. Explanation: The wavelengths of the first four lines in the visible spectrum of hydrogen from Table 29.1 are 656.6 nm, 486.3 nm 434.2 nm and 410.3 nm. For first wavelength 656.6 nm, Substitute 656.6 nm for λ in equation (1), 1 m 2 − 1 n 2 = 91.1 nm 656.6 nm n 2 − m 2 n 2 m 2 = 0.1387 n 2 − m 2 n 2 m 2 ≅ 0.139 Substitute m + 1 for n , ( m + 1 ) 2 − m 2 ( m + 1 ) 2 × m 2 = 0.139 { ∵ n = m + 1 } ( m + 1 ) 2 − m 2 = 0 b. To determine The wavelength of the fifth line spectrum.

Student Workbook For College Physics Format: Paper

4th Edition

ISBN: 9780134724805

Author: Knight, Randall D., (professor Emeritus)^jones, Br

Publisher: Prentice Hall

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Question

Chapter 29, Problem 1P

To determine

The Balmer formula n and m values.

To determine

The wavelength of the fifth line spectrum.

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Chapter 29, Problem 32MCQ

Chapter 29, Problem 2P

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