Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (3rd Edition)
3rd Edition
ISBN: 9780321908803
Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher: PEARSON
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Chapter 29, Problem 2CQ
To determine
To explain: The difference between emission spectrum and absorption spectrum.
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A hydrogen atom in the ground state absorbs a 13.32-eV photon. To what level is the electron promoted? (The ionization energy of hydrogen is 13.6 eV).
a.
n = 6
b.
n = 5
c.
n = 10
d.
n = 11
e.
n = 7
QUESTION 10
Which of these expressions would yield the wavelength of light in meters emitted when an electron drops from orbit n = 3 to n = 2 in a Bohr hydrogen atom? Given h = 4.14 x 10-15 eVs and c = 3.00 x 108 m/s.
a.
hc/1.89
b.
1.89 x h x c
c.
1.89/hxc
d.
(1.51 + 3.4)/hc
e.
hc/3.4
With no magnetic field, the spectral line representing the transition from the 2P1/2 state to the 2S1/2 state in sodium has the wavelength 589.76 nm (see Figure). This is one of the two strong yellow lines in sodium. Calculate the difference in wavelength between the shortest and longest wavelength between these two states when placed in a magnetic field of 2.50 T.
Chapter 29 Solutions
Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (3rd Edition)
Ch. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQCh. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - Prob. 8CQCh. 29 - Prob. 9CQCh. 29 - Prob. 10CQ
Ch. 29 - Prob. 11CQCh. 29 - Prob. 12CQCh. 29 - Prob. 13CQCh. 29 - Prob. 14CQCh. 29 - Prob. 15CQCh. 29 - Prob. 16CQCh. 29 - Prob. 17CQCh. 29 - Prob. 18CQCh. 29 - Prob. 19CQCh. 29 - Prob. 20CQCh. 29 - Prob. 21CQCh. 29 - Prob. 22CQCh. 29 - Prob. 23CQCh. 29 - Prob. 24MCQCh. 29 - Prob. 25MCQCh. 29 - Prob. 26MCQCh. 29 - Prob. 27MCQCh. 29 - Prob. 28MCQCh. 29 - Prob. 29MCQCh. 29 - Prob. 30MCQCh. 29 - Prob. 1PCh. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Prob. 4PCh. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - Prob. 9PCh. 29 - Prob. 10PCh. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - Prob. 14PCh. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Prob. 19PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - Prob. 24PCh. 29 - Prob. 25PCh. 29 - Prob. 26PCh. 29 - Prob. 27PCh. 29 - Prob. 28PCh. 29 - Prob. 29PCh. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - Prob. 35PCh. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 38PCh. 29 - Prob. 39PCh. 29 - Prob. 40PCh. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 44GPCh. 29 - Prob. 45GPCh. 29 - Prob. 46GPCh. 29 - Prob. 47GPCh. 29 - Prob. 48GPCh. 29 - Prob. 49GPCh. 29 - Prob. 50GPCh. 29 - Prob. 51GPCh. 29 - Prob. 52GPCh. 29 - Prob. 53GPCh. 29 - Prob. 54GPCh. 29 - Prob. 55GPCh. 29 - Prob. 56GPCh. 29 - Prob. 57GPCh. 29 - Prob. 58GPCh. 29 - Prob. 59GPCh. 29 - Prob. 60GPCh. 29 - Prob. 61GPCh. 29 - Prob. 62GPCh. 29 - Prob. 63GPCh. 29 - Prob. 64GPCh. 29 - Prob. 65GPCh. 29 - Prob. 66GPCh. 29 - Prob. 67GPCh. 29 - Prob. 68GPCh. 29 - Prob. 69GPCh. 29 - Prob. 70GPCh. 29 - Prob. 71GPCh. 29 - Prob. 73GPCh. 29 - Prob. 74GPCh. 29 - Prob. 75GPCh. 29 - Prob. 76MSPPCh. 29 - Prob. 77MSPPCh. 29 - Prob. 78MSPPCh. 29 - Prob. 79MSPP
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- Explain why spectral lines of the hydrogen atom are split by an external magnetic field. What determines the number and spacing of these lines?arrow_forwardAn electron in hydrogen absorbs a photon and jumps from orbit n = 2 to n = 4. Using the energy level diagram shown, what was the energy of the absorbed photon? a. 3.4 eV b. 10.2 eV c. 0.85 eV d. 0 eV e. 2.55 eVarrow_forwardWhat is the energy of the absorbed photon that causes a hydrogen atom to transit from ground state to the state for which n = 3? Group of answer choices 1.51 eV 4.53 eV 13.6 eV 12.1 eVarrow_forward
- As shown the energy-level diagram of Element X.a. What is the ionization energy of Element X?b. An atom in the ground state absorbs a photon, then emits a photon with a wavelength of 1240 nm. What conclusion can you draw about the energy of the photon that was absorbed?c. An atom in the ground state has a collision with an electron, then emits a photon with a wavelength of 1240 nm. What conclusion can you draw about the initial kinetic energy of the electron?arrow_forwardA photon is emitted when a hydrogen atom undergoes a transition from the n = 9 state to the n = 1 state. Calculate values for the following. (a) the wavelength (in nm) (b) the frequency (in Hz) (c) the energy of the emitted photon (eV)arrow_forwardAn electron is in the first excited state, n = 2, of a Hydrogen atom. What wavelength of light would be the maximum required to ionise this excited electron? Select one: a. 820.0 nm b. 1.46 μm c. 91.28 nm d. 364.6 nm Clear my choicearrow_forward
- a) Find the energy necessary to raise an electron from states n = 4 to n = 5 in the hydrogen atom.b) Find the radius of orbit n = 4 for a doubly ionized lithium atom (Li2 +, Z = 3).c.) Find the energy necessary to raise an electron from state n = 4 to state n = 5 in Li2 +.arrow_forwardWhich of these expressions would yield the wavelength of light in meters emitted when an electron drops from orbit n = 3 to n = 2 in a Bohr hydrogen atom? Given h = 4.14 x 10-15 eVs and c = 3.00 x 108 m/s. a. 1.89/hxc b. hc/1.89 c. 1.89 x h x c d. (1.51 + 3.4)/hc e. hc/3.4arrow_forward51. (a) Calculate the wavelength (in nm) of light with energy 1.61×10−20 J per photon. (b) For light of wavelength 440 nm, calculate the number of photons per joule. (c) Determine the binding energy (in eV) of a metal if the kinetic energy possessed by an ejected electron (using one of the photons with wavelength 440 nm) is 2.53×10−19 J.arrow_forward
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