(a)
The RMS current in all branch of the circuit if frequency is 500 Hz.
(a)
Answer to Problem 41P
Explanation of Solution
Given:
Load resistance is
Inductance of inductor is
Resistance of resistor is
Frequency is
Ideal voltage output is
Formula used:
Phase angle is expressed as
Here,
Resultant reactance for parallel combination is is
Here,
Peak current is
Calculation:
Substitute
Substitute
Therefore, final value of
Substitute 100 V for
RMS current is
And
The current for resistor and inductor are
And
Conclusion:
Hence, the requiredcurrent across each branch are
(b)
RMS current in all branch of the circuit if frequency is 2000 Hz.
(b)
Answer to Problem 41P
The required current across each branch are
Explanation of Solution
Given:
Load resistance is
Inductance of inductor is
Resistance of resistor is
Frequency is
Ideal voltage output is
Formula used:
Phase angle is expressed as
Here,
Resultant inductance is
Here,
Peak current is
Calculation:
Substitute
Substitute
Therefore, final value of
Substitute 100 V for
RMS current is
And
The current for resistor and inductor are
And
Conclusion:
Hence, the required current across each branch are
(c)
The fraction of the total average power supplied by the ac generator that is delivered to the load resistor if the frequency is 500 Hz.
(c)
Answer to Problem 41P
Explanation of Solution
Given:
Load resistance is
Inductance of inductor is
Resistance of resistor is
Frequency is
RMS current is
RMS current across
Ideal voltage output is
Formula used:
The fraction of the total power delivered by the source that is dissipated in load resistor can be expressed as
Here,
Calculation:
Substitute 500 Hz for
Conclusion:
Hence, the required the fraction of the total average power supplied by the ac generator that is delivered to the load resistor if the frequency is 500 Hz is
(d)
The fraction of the total average power supplied by the ac generator that is delivered to the load resistor if the frequency is 2000 Hz.
(d)
Answer to Problem 41P
Explanation of Solution
Given:
Load resistance is
Inductance of inductor is
Resistance of resistor is
Frequency is
RMS current is
RMS current across
Ideal voltage output is
Formula used:
The fraction of the total power delivered by the source that is dissipated in load resistor can be expressed as
Here,
Calculation:
Substitute 2000 Hz for
Conclusion:
Hence, the required the fraction of the total average power supplied by the ac generator that is delivered to the load resistor if the frequency is 2000 Hz is
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Chapter 29 Solutions
Physics For Scientists And Engineers Student Solutions Manual, Vol. 1
- The output voltage of an AC generator is given by Δ v = (170 V) sin (60πt). The generator is connected across a 20.0-Ω resistor. By inspection, what are the (a) maximum voltage and (b) frequency? Find the (c) rms voltage across the resistor, (d) rms current in the resistor, (e) maximum current in the resistor, (f) power delivered to the resistor, and (g) current when t = 0.005 0 s. (h) Should the argument of the sine function be in degrees or radians? GIVEN: Output voltage, Δv = (170 V) sin (60πt) Resistance, R = 20.0-Ω arrow_forward Step 2 Part (a) Part (a) Standard equation can be represented as, Δv = Vmsin(ωt) Where, Vm = maximum voltage. ω = angular frequency. Compare the given equation with standard equation. We get, Vm = 170 V Answer arrow_forward Step 3 Part (b) Part (b) Angular frequency, ω = 60π ... (1) Also, ω = 2πf .... (2) Equate both, 2πf = 60π f = 60π/2π f = 30 Hz Answer arrow_forward Step 4 Part (c) Part (c) RMS voltage is…arrow_forwardConsider an AC power supply with the frequency f = 100 Hz connected to an inductor (L = 0.3 H), capacitor (C = 2e-05 F) and resistor (R = 32 Ohm) in series. The maximum current in the AC circuit Imax = 0.4 A. What is the maximum applied voltage?arrow_forwardAn AC voltage of the form Δv 5 (90.0 V) sin (350t) isapplied to a series RLC circuit. If R = 50.0 Ω, C = 25.0 µF,and L = 0.200 H, find the (a) impedance of the circuit,(b) rms current in the circuit, and (c) average power deliveredto the circuit.arrow_forward
- A series RLC circuit has a capacitance C=305μF, an inductance L=131 mH, and is driven by an AC generator producing a root‑mean‑square (rms) voltage Vrms=120.0 V with a frequency f=60.0 Hz. What resistance R is necessary to produce an rms current Irms=2.05 A?arrow_forwardThe self-inductance and capacitance of an LC circuit e 0.20 mH and 5.0 pF. What is the angular frequency at which the circuit oscillates?arrow_forwardCalculate the rms currents for an ac source is given by v(t)=v0sint , where V0=100V and =200rad/s when connected across (a) a 20F capacitor, (b) a 20-mH inductor, and (c) a 50 resistor.arrow_forward
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