COLLEGE PHY2053 W/MODIFIED ACCESS>BI<
16th Edition
ISBN: 9781323515303
Author: Knight
Publisher: PEARSON C
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Chapter 29, Problem 4CQ
To determine
To explain: The nuclei of same element that have different values of
To determine
To explain: The nuclei of different element that have same values of
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Chapter 29 Solutions
COLLEGE PHY2053 W/MODIFIED ACCESS>BI<
Ch. 29 - Prob. 1CQCh. 29 - Prob. 2CQCh. 29 - Prob. 3CQCh. 29 - Prob. 4CQCh. 29 - Prob. 5CQCh. 29 - Prob. 6CQCh. 29 - Prob. 7CQCh. 29 - Prob. 8CQCh. 29 - Prob. 9CQCh. 29 - Prob. 10CQ
Ch. 29 - Prob. 11CQCh. 29 - Prob. 12CQCh. 29 - Prob. 13CQCh. 29 - Prob. 14CQCh. 29 - Prob. 15CQCh. 29 - Prob. 16CQCh. 29 - Prob. 17CQCh. 29 - Prob. 18CQCh. 29 - Prob. 20CQCh. 29 - Prob. 21CQCh. 29 - Prob. 22CQCh. 29 - Prob. 23CQCh. 29 - Prob. 24CQCh. 29 - Prob. 25CQCh. 29 - Prob. 27MCQCh. 29 - Prob. 28MCQCh. 29 - Prob. 29MCQCh. 29 - Prob. 30MCQCh. 29 - Prob. 31MCQCh. 29 - Prob. 32MCQCh. 29 - Prob. 1PCh. 29 - Prob. 2PCh. 29 - Prob. 3PCh. 29 - Prob. 4PCh. 29 - Prob. 5PCh. 29 - Prob. 6PCh. 29 - Prob. 7PCh. 29 - Prob. 8PCh. 29 - Prob. 9PCh. 29 - Prob. 10PCh. 29 - Prob. 11PCh. 29 - Prob. 12PCh. 29 - Prob. 13PCh. 29 - Prob. 14PCh. 29 - Prob. 15PCh. 29 - Prob. 16PCh. 29 - Prob. 17PCh. 29 - Prob. 18PCh. 29 - Prob. 19PCh. 29 - Prob. 20PCh. 29 - Prob. 21PCh. 29 - Prob. 22PCh. 29 - Prob. 23PCh. 29 - Prob. 24PCh. 29 - Prob. 25PCh. 29 - Prob. 27PCh. 29 - Prob. 28PCh. 29 - Prob. 29PCh. 29 - Prob. 30PCh. 29 - Prob. 31PCh. 29 - Prob. 32PCh. 29 - Prob. 33PCh. 29 - Prob. 34PCh. 29 - Prob. 35PCh. 29 - Prob. 36PCh. 29 - Prob. 37PCh. 29 - Prob. 39PCh. 29 - Prob. 40PCh. 29 - Prob. 41PCh. 29 - Prob. 42PCh. 29 - Prob. 43PCh. 29 - Prob. 45PCh. 29 - Prob. 46PCh. 29 - Prob. 47PCh. 29 - Prob. 48PCh. 29 - Prob. 49PCh. 29 - Prob. 50PCh. 29 - Prob. 51PCh. 29 - Prob. 52GPCh. 29 - Prob. 53GPCh. 29 - Prob. 54GPCh. 29 - Prob. 55GPCh. 29 - Prob. 56GPCh. 29 - Prob. 57GPCh. 29 - Prob. 58GPCh. 29 - Prob. 59GPCh. 29 - Prob. 60GPCh. 29 - Prob. 61GPCh. 29 - Prob. 62GPCh. 29 - Prob. 63GPCh. 29 - Prob. 64GPCh. 29 - Prob. 65GPCh. 29 - Prob. 66GPCh. 29 - Prob. 67GPCh. 29 - Prob. 69GPCh. 29 - Prob. 70MSPPCh. 29 - Prob. 71MSPPCh. 29 - Prob. 72MSPPCh. 29 - Prob. 73MSPPCh. 29 - Prob. 74MSPPCh. 29 - Prob. 75MSPPCh. 29 - Prob. 77MSPP
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- (a) Show that if you assume the average nucleus is spherical with a radius r=r0A1/3, and with a mass at A u, then its density is independent at A. (b) Calculate that density in u/fm3 and kg/m3, and compare your results with those found in Example 31.1 for 56Fe.arrow_forwardIdentify the shell, subshell, and number of electrons for the following: (a) 2P3. (b)4d9. (c) 3s1. (d) 5g16.arrow_forwardSomeone wanted to build a scale model of the atom with a nucleus 1.4 m in diameter. How far away would the nearest electron need to be in meters? Assume the orbital radius of an electron is 10^(-10)m, while the radius of the nucleus is 10^(-15) m. ra=?arrow_forward
- Before the neutron was discovered, the only possible constitution of a nucleus with a given (A,Z) was A protons and (A-Z) electrons, leaving a net charge of +Ze. Early indications were that the nitrogen nucleus (A = 14,Z = 7) had a total angular mo- mentum that was an integral multiple of ħ. Is this consistent with a nucleus made of A protons and A-Z electrons? How does the inclusion of neutrons change things?arrow_forwardTwo electrons in the nucleus of a 238U atom are separated by a distance of 8 fm. What is the potential energy of the arrangement? A) 179.77 keVB) 2.25×10 43 eVC) 4.61×10 −33 keVD) 3.596 eVarrow_forward1. In Rutherford’s scattering experiments, alpha particles acharge = +2ef were fired at a gold foil. Consider analpha particle with an initial kinetic energy K heading directly for the nucleus of a gold atomacharge = +79ef. The alpha particle will come to rest when all its initial kinetic energy has been converted toelectrical potential energy. Find the distance of closest approach between the alpha particle and the gold nucleusfor the case K = 3.0 MeVarrow_forward
- The electron in the hydrogen atom (in its ground state) orbits the nucleus at a distance of 0.5292 Å. (a) Calculate the gravitational force and (b) the electrostatic force of attraction between the two. (c) Comment on the magnitude and the importance of these two forces. [G, gravitational constant = 6.672 x 10-11 N m2 kg-2; 4πЄo = 1.113 x 10-10 C2 m-1 J-1]arrow_forwardFrom far away a proton is fired directly toward the center of the nucleus of a mercury atom. Mercury is element number 80, and the diameter of the nucleus is 14.0 fm. Assume the mercury nucleus is fully-ionized, with no electrons bound to it. If the proton is fired at a speed of 3.8×107 m/s, what is its closest approach to the surface of the nucleus? Assume the nucleus remains at rest. Express your answer with the appropriate units. ► View Available Hint(s) 0 d = 2.7 Submit A fm Previous Answers ? X Incorrect; Try Again; 13 attempts remainingarrow_forwardQUESTION 19 In 1911, when Rutherford observed alpha particles being scattered at back angles from a gold foil, he reached the conclusion that alpha particles are helium nuclei. alpha particles are very tightly bound. the plum-pudding model of the atom must be wrong . gold has a much higher atomic number than previously thought.arrow_forward
- 3) Assume that this room was filled with a gas of oxygen molecules O₂ in thermal equilibrium at 0 °C. There are 8 protons and 8 neutrons in the nucleus of an oxygen atom O. You may take the masses of the proton and the neutron to be the same, and ignore the mass of the electrons. 1 atm=1.01x105 N/m², h=1.05x10-34 J-s, mp=1.67x10-27 kg, ka=1.38x10-23 J/K. a) What would the (particle) number density, n, be according to the ideal gas law? b) Compare the number density with the quantum concentration, no, at the same temperature. Is the gas in the classical or quantum regime?arrow_forwardA sodium atom (Z = 11) contains 11 protons in its nucleus. Strictly speaking, the Bohr model does not apply, because the neutral atom contains 11 electrons instead of a single electron. However, we can apply the model to the outermost electron as an approximation, provided that we use an effective value Zeffective rather than 11 for the number of protons in the nucleus. (a) The ionization energy for the outermost electron in a sodium atom is 5.1 eV. Use the Bohr model with Z = Zeffective to calculate a value for Zeffective. (b) Using Z = 11, determine the corresponding value for the radius r of the outermost Bohr orbit. (c) Using the value calculated for Zeffective in part (a), determine the corresponding radius r of the outermost Bohr orbit. (a) Zeffective (b) r = (c) r= Number i Number i Number i Units Units Unitsarrow_forwardA sodium atom (Z = 11) contains 11 protons in its nucleus. Strictly speaking, the Bohr model does not apply, because the neutral atom contains 11 electrons instead of a single electron. However, we can apply the model to the outermost electron as an approximation, provided that we use an effective value Zeffective rather than 11 for the number of protons in the nucleus. (a) The ionization energy for the outermost electron in a sodium atom is 5.1 eV. Use the Bohr model with Z = Zeffective to calculate a value for Zeffective. (b) Using Z = 11, determine the corresponding value for the radius r of the outermost Bohr orbit. (c) Using the value calculated for Zeffective in part (a), determine the corresponding radius r of the outermost Bohr orbit. (a) Zeffective = Number i 2.04 (b) _r= (c)_r= Number i 5.29E-11 Number i 2.12E-11 Units No units Units m Units m ♥arrow_forward
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