Explanation Given data: Rate of photon emission is 10 29 photons m 2 ⋅ s . Wavelength of the laser beam is 500 nm. Formula used: Write the expression for energy. E = h c λ (1) Here, E is the energy, h is the Planck’s constant with value 6.62 × 10 − 34 m 2 ⋅ kg s , c is the speed of the light 3 × 10 8 m s , and λ is the wavelength. Consider the expression for intensity. I = Rate of photon emission × Energy of each photon (2) Here, I is the intensity. Explanation: For energy of each photon, Each photon will use double the wavelength of 500 nm, so the wavelength of the photons is λ = 1000 nm Substitute 6.62 × 10 − 34 m 2 ⋅ kg s for h , 3 × 10 8 m s for c and 1000 × 10 − 9 m for λ in equation (2), E = ( 6.62 × 10 − 34 m 2 ⋅ kg s ) ( 3 × 10 8 m s ) 350 × 10 − 9 m = ( 1

Modified Mastering Physics with Pearson eText -- Standalone Access Card -- for College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321943798

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Chapter 29, Problem 75GP

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Minimum intensity of the laser beam during each pulse.

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Chapter 29, Problem 74GP

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Chapter 29 Solutions

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Minimum intensity of the laser beam during each pulse.

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Minimum intensity of the laser beam during each pulse.

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