Concept explainers
Interpretation:
The difference between
Concept Introduction:
The steps involved to name a molecular compound are as follows:
First, identify that the given compound involves the combination of two non-metals or a non-metal and a metalloid.
Identify the
Start the name with the name of the first element in the compound.
If more than one atom is present, use prefixes as di, tri, and tetra.
Then, state the root name of the second element with a proper suffix.
The naming representation for an acid starts with ‘hydro’ as the prefix followed by the name of the metal or non-metal with the use of ‘ic’ as a suffix.
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Introduction To Chemistry
- Which of these statements are qualitative? Which are quantitative? Explain your choice in each case. (a) Sodium is a silvery-white metal. (b) Aluminum melts at 660 C. (c) Carbon makes up about 23% of the human body by mass. (d) Pure carbon occurs in different forms: graphite, diamond, and fullerenes.arrow_forwardNeutralization reactions involve the hydrogen ions (H+) from an acid, reacting with a base that often contains hydroxide ions (OH). Use this information to predict the name and formula for the chemical substance that is always produced in this type of reaction.arrow_forwardThe elements of Group 1-B (Cu, Ag, and Au) are sometimes referred to as the “coinage metals.” Why? What properties do they have that make them particularly useful for this purpose?arrow_forward
- Matter is neither created nor destroyed in a chemical reaction. Thus, the mass of the products of a chemical reaction must be equal to the mass of the starting materials. Formally, this concept is called the law of conservation of mass. A sample of sodium reacts completely with 0.426 kg k g of chlorine, forming 702 g g of sodium chloride. What mass of sodium reacted?arrow_forwardOver coffee and croissants at breakfast one day, your friend Jane (an expert chemist) says this: "Metal sulfides react with strong acids to produce hydrogen sulfide and a salt." Using Jane's statement, and what you already know about chemistry, predict the products of the following reaction. Be sure your chemical equation is balanced! Nis (s) + HCl(aq) → 0 ローロ 0+0 X C READarrow_forwardCrime scene investigators keep a wide variety of compounds on hand to help with identifying unknown substances they find in the course of their duties. One such investigator, while reorganizing their shelves, has mixed up several small vials and is unsure about the identity of a certain powder. Elemental analysis of the compound reveals that it is 67.31 % carbon, 6.978% hydrogen, 4.617% nitrogen, and 21.10% oxygen by mass. Which of the compounds could the powder be? C17H19NO3C17H19NO3 = morphine, analgesic C17H21NO4C17H21NO4 = cocaine, illicit drug C7H5N3O6C7H5N3O6 = 2,4,6-trinitrotoluene (TNT), commonly used explosive C10H15NC10H15N = methamphetamine, stimulant C4H5N2OC4H5N2O = caffeine, stimulant C11H15NO2C11H15NO2 = 3,4-methylenedioxymethamphetamine (MDMA), illicit drug C21H23NO5C21H23NO5 = heroin, illicit drug C3H6NO3C3H6NO3 = hexamethylene triperoxide diamine (HMTD), commonly used explosivearrow_forward
- One way the U.S. Environmental Protection Agency (EPA) tests for chloride contaminants in water is by titrating a sample of silver nitrate solution. Any chloride anions in solution will combine with the silver cations to produce bright white silver chloride precipitate. Suppose an EPA chemist tests a 200. mL sample of groundwater known to be contaminated with iron(III) chloride, which would react with silver nitrate solution like this: FeCl3(aq) + 3 AgNO3(aq) 3 AgCl(s) + Fe(NO3),(a9) The chemist adds 56.0 mM silver nitrate solution to the sample until silver chloride stops forming. She then washes, dries, and weighs the precipitate. She finds she has collected 2.8 mg of silver chloride. Calculate the concentration of iron(III) chloride contaminant in the original groundwater sample. Be sure your answer has the correct number of significant digits. mg L Submit Assignment Continue Accessibility Privacy O 2020 McGraw-Hill Education. All Rights Reserved. Terms of Use 888 %23 5 6 2 3 E R. G…arrow_forwardAn alloy contains 10.8 % titanium by mass and has a density of 13.98 g/cm3. Titanium-49 has an isotopic abundance 6.82 %. Calculate the volume (cm3) of alloy required that contains 8,926,980,280,926,177,000,000 atoms of titanium-49. Submit your answer with no units and to two decimal places.arrow_forwardPredicting the reactants of a neutralization reaction Predict the reactants of this chemical reaction. That is, fill in the left side of the chemical equation. Be sure the equation you submit is balanced. (You can edit both sides of the equation to balance it, if you need to.) Note: you are writing the molecular, and not the net ionic equation. [] + KCIO(aq) + H,O(1) X ロー Śarrow_forward
- The density of gold metal is 19.3 g/cm3, while that for silver is 10.5 g/cm3. Suppose you had the same size bar of each metal, with the dimensions 2.00 in x 10.0 cm x 760 mm. Volume of a cube is height x length x width. Which bar would have the greatest mass? Which bar contains the greater number of atoms? If the two bars were melted and mixed together to form an alloy (or mixture) what would be the total mass?arrow_forwardA solution is formed by dissolving 2.000 kg of sugar (sucrose, density = 1587 kg·m−3) in 1.000 kg of water (density = 1000 kg·m−3). Assume that the volume of the solution formed is the sum of the sugar volume and the water volume. a) What is the final volume of the solution? b) What is the density of the solution?arrow_forwardThe maximum contaminant level of fluoride (F−)(F−) in drinking water as set by the the Environmental Protection Agency (EPA) is 0.0040 g⋅L−10.0040 g⋅L−1. Express this concentration in parts per million (ppm). Assume the density of water is 1.00 g/mL1.00 g/mL.arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning