University Physics Volume 2
18th Edition
ISBN: 9781938168161
Author: OpenStax
Publisher: OpenStax
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Textbook Question
Chapter 3, Problem 17CQ
There is no change in the internal of an ideal gas undergoing an isothermal process since the internal energy depends only on the temperature. Is it therefore correct to say that an isothermal process is the same as an adiabatic process for an ideal gas? Explain your answer.
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Repeat the preceding calculations for an ideal diatomic gas expanding adiabatically from an initial volume of 0.500 m3 to a final volume of 1.25 m3, starting at a pressure of 1.01 105 Pa. (You must sketch the curve to find the work.)
P2 = PaW ≈ J
Repeat the preceding calculations for an ideal diatomic gas expanding adiabatically from an initial volume of 0.500 m3 to a final volume of 1.25 m3, starting at a pressure of 1.01 105 Pa. (You must sketch the curve to find the work.)
P2 = W ≈
A monatomic ideal gas with volume 0.185 L is rapidly compressed, so the process can be considered adiabatic. If the gas is initially at 1.01 105 Pa and 3.00 102 K and the final temperature is 475 K, find the work done by the gas on the environment, Wenv.Wenv = J
Chapter 3 Solutions
University Physics Volume 2
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