Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 3, Problem 17P
Solution

(a)

To Determine:The two possible values for x -component.

Solution: ±62.25

Explanation:

Given:

The resultant magnitude is |V|=90 .

The y-component of Vy vector V is -65.0.

Formula used:

The magnitude of vector can be obtained by:

  |V|=(Vx2)+( V y )2

And, the direction θ is defined as:

  θ=tan1(VyVx)

Calculation:

Substitute the values and solve:

  |V|=( V x 2 )+ ( V y )290= ( V x )2+ ( 65 )2Vx=±( 90 2 ( 65 ) 2 )Vx=±62.25

Conclusion:

Thus, the two possible values of x-component are ±62.25 .

(b)

To Determine: A vector that can be added to the positive x -component to give resultant of 80 units in negative x -direction.

Solution:A vector U can be added which has a magnitude of 156.4 and directed 155.5o counter clockwise from positive x -axis.

Given:

The resultant vector is V+U=80i^ .

The x -component of vector V is Vx=62.25 .

The y-component of Vy vector V is -65.0.

Formula used:

The magnitude of vector can be obtained by:

  |V|=(Vx2)+( V y )2

And, the direction θ is defined as:

  θ=tan1(VyVx)

Calculation:

Consider the vector to be added: U

Then,

  Vy+Uy=065+Uy=0Uy=65

And

  Vx+Ux=8062.25+Ux=80Ux=142.25

Substitute the values and solve to find the resultant of vector U

  |U|=( U x 2 )+ ( U y )2= ( 142.25 )2+ ( 65 )2=156.4

  θ=tan1( U y U x )=tan1( 65 142.25)=24.6o=18024.6=155.5o

Conclusion:

Thus, a vector U can be added which has a magnitude of 156.4 and directed 155.5o counter clockwise from positive x -axis.

Chapter 3 Solutions

Physics: Principles with Applications

Ch. 3 - Prob. 11QCh. 3 - Prob. 12QCh. 3 - Prob. 13QCh. 3 - A projectile is launched at an upward angle of 300...Ch. 3 - Prob. 15QCh. 3 - Two cannonballs, A and B, are fired from the...Ch. 3 - 18. A person sitting in an enclosed train car,...Ch. 3 - Prob. 18QCh. 3 - Prob. 19QCh. 3 - Prob. 20QCh. 3 - A car is driven 225 km west and then 98 km...Ch. 3 - A delivery truck travels 21 blocks north, 16...Ch. 3 - If Vx=9.80 units and Vy=6.40 units, determine the...Ch. 3 - Graphically determine the resultant of the...Ch. 3 - V is a vector 24.8 units in magnitude and points...Ch. 3 - Vector V is 6.6 using long and points along the...Ch. 3 - Figure 3-33 shows two vectors, A and B , whose...Ch. 3 - Prob. 8PCh. 3 - Three vectors are shown in Fig. 3-35 Q. Their...Ch. 3 - (a) given the vectors A and B shown in Fig. 3-35,...Ch. 3 - Determine the vector AC , given the vectors A and...Ch. 3 - For the vectors shown in Fig. 3—35, determine (a)...Ch. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - 17. (l) A tiger leaps horizontally from a...Ch. 3 - 18. (l) A diver running 2.5 m/s dives out...Ch. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53GPCh. 3 - Prob. 54GPCh. 3 - Prob. 55GPCh. 3 - Prob. 56GPCh. 3 - Prob. 57GPCh. 3 - Prob. 58GPCh. 3 - Prob. 59GPCh. 3 - Prob. 60GPCh. 3 - Prob. 61GPCh. 3 - Prob. 62GPCh. 3 - Prob. 63GPCh. 3 - Prob. 64GPCh. 3 - Prob. 65GPCh. 3 - Prob. 66GPCh. 3 - Prob. 67GPCh. 3 - Prob. 68GPCh. 3 - Prob. 69GPCh. 3 - Prob. 70GPCh. 3 - Prob. 71GPCh. 3 - Prob. 72GPCh. 3 - Prob. 73GPCh. 3 - Prob. 74GPCh. 3 - Prob. 75GP
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