Chapter 3, Problem 21E

Explanation of Solution

a.

Query:

select memb_no, name from member natural join borrowed where isbn in (select isbn from book where publisher=’McGraw-Hill’);

Explanation:

Explanation of Solution

b.

Query:

Select memb_no, name from member m where not exists

(select isbn from book where publisher=’McGraw-Hill’ except (select isbn from member natural join borrowed where m.memb_no=memb_no));

Explanation:

The above query is get the “memb_n...

Explanation of Solution

c.

Query:

Select memb_no, name from member natural join borrowed natural join book group by memb_no, name, publisher having count (isbn)>5...

Explanation of Solution

d.

Query:

select sum(num_of_books)/ count(memb_no) from (select memb_no, (select count(*) from borrowed where member.memdber_no=borrowed...

Explanation of Solution

e.

Query:

create table participated (report_number char(20) primary key, license char(20) references car, driver_id char(20) references driver, damage_amount dec(6,2) )

Explanation:

The above query is used creat...