Introduction To Genetic Analysis
12th Edition
ISBN: 9781319114787
Author: Anthony J.F. Griffiths, John Doebley, Catherine Peichel, David A. Wassarman
Publisher: W. H. Freeman
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Chapter 3, Problem 25P
Summary Introduction
To determine: The genotype among the given genotypes that might represent possible daughter cells.
a. A; B
b. a; b
c. A; b
d. n; R
e. A/A; B/B
f. A/a ; B/b
g. a/a; b/b
Introduction: Somatic cells are every cell in the body besides the gametes, and they have a full set of chromosomes and replicate in mitosis for the body to repair damaged tissue and grow. In humans, a diploid cell has 46 chromosomes.
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Students have asked these similar questions
Possible options:
A. Autopolyploidy
B. Allopolyploidy
C. Chromosome duplication
D. Pericentric inversion
The amount of DNA in a cell in G1 can be represented as 2C. The amount of DNA in a cell in telophase II is:
a. C
b. 2C
c. 4C
d. 8C
e. none of these
...explain your answer
The image shows a homologous pair of chromosomes. Now imagine a crossing over event occurring between a chromatid on one chromosome and a chromatid on the other chromosome. This cross over occurs between the S and T loci. What are the genotypes of the two chromatids after the crossover?
ANSWER CHOICES
A. grsT and GRSt
B. impossible to know
C. grst and GRST
D. GrSt and gRsT
Chapter 3 Solutions
Introduction To Genetic Analysis
Ch. 3 - Prob. 1PCh. 3 - Prob. 2PCh. 3 - Prob. 3PCh. 3 - Prob. 4PCh. 3 - Prob. 5PCh. 3 - Prob. 6PCh. 3 - Prob. 7PCh. 3 - Prob. 8PCh. 3 - Prob. 9PCh. 3 - Prob. 10P
Ch. 3 - Prob. 11PCh. 3 - Prob. 12PCh. 3 - Prob. 13PCh. 3 - Prob. 14PCh. 3 - Prob. 15PCh. 3 - Prob. 16PCh. 3 - Prob. 17PCh. 3 - Prob. 18PCh. 3 - Prob. 19PCh. 3 - Prob. 20PCh. 3 - Prob. 21PCh. 3 - Prob. 22PCh. 3 - Prob. 23PCh. 3 - Prob. 24PCh. 3 - Prob. 25PCh. 3 - Prob. 26PCh. 3 - Prob. 27PCh. 3 - Prob. 28PCh. 3 - Prob. 29PCh. 3 - Prob. 30PCh. 3 - Prob. 31PCh. 3 - Prob. 32PCh. 3 - Prob. 33PCh. 3 - Prob. 34PCh. 3 - Prob. 35PCh. 3 - Prob. 36PCh. 3 - Prob. 37PCh. 3 - Prob. 38PCh. 3 - Prob. 39PCh. 3 - Prob. 40PCh. 3 - Prob. 41PCh. 3 - Prob. 42PCh. 3 - Prob. 43PCh. 3 - Prob. 43.1PCh. 3 - Prob. 43.2PCh. 3 - Prob. 43.3PCh. 3 - Prob. 43.4PCh. 3 - Prob. 43.5PCh. 3 - Prob. 43.6PCh. 3 - Prob. 43.7PCh. 3 - Prob. 43.8PCh. 3 - Prob. 43.9PCh. 3 - Prob. 43.10PCh. 3 - Prob. 43.11PCh. 3 - Prob. 43.12PCh. 3 - Prob. 43.13PCh. 3 - Prob. 43.14PCh. 3 - Prob. 43.15PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - Prob. 47PCh. 3 - Prob. 48PCh. 3 - Prob. 49PCh. 3 - Prob. 50PCh. 3 - Prob. 51PCh. 3 - Prob. 52PCh. 3 - Prob. 53PCh. 3 - Prob. 54PCh. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - Prob. 58PCh. 3 - Prob. 59PCh. 3 - Prob. 61PCh. 3 - Prob. 62PCh. 3 - Prob. 63PCh. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - Prob. 66PCh. 3 - Prob. 67PCh. 3 - Prob. 70PCh. 3 - Prob. 1GSCh. 3 - Prob. 2GSCh. 3 - Prob. 3GS
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- 2) A. Explain how polyribosomes form. B. Why might you expect the insertion of 3 DNA base pairs to be less disruptive than th deletion of a single base pair? C. Compare and contrast mitosis and meiosis with respect to their genetic outcomes? D. What are the possible consequences of non-disjunction during cell division? E. How does meiosis increase genetic diversity in populations?arrow_forwardGenes G and H are located on chromosome 18. A woman with the genotype Gg Hh has a child with a man with the genotype GG HH. Unfortunately, the child has the genotype Ggg hhh and only survives for 6 months. When and in which parent did nondisjunction occur? Group of answer choices a. Meiosis II in the mother b. Meiosis I in the mother c. Meiosis I in the father d. Meiosis II in the fatherarrow_forwardA patient has mental deficiency, a short stature, and the mongolian type of the eyelid fold. The microscopical examination of the patient's karyotype revealed the presence of trisomy on the 21-st chromosome. What do we call the disease which is caused by this chromosomal abnormality? Select one: a. Down's syndrome. b. Klinefelter's syndrome. O c. Turner's syndrome. d. Edward's syndrome. e. Patau syndrome.arrow_forward
- In this image of the human karyotype: A. The sister chromatids have separated B. There are 46 pairs of chromosomes C. The DNA has already been replicated D. There are 23 pairs of autosomes E. None are true.arrow_forwardIn this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected I || IV V TOLO 5 DO 머 9 10 a. Any of these options is possible b. III.5 but not V.3 would display the disease O c. V.3 but not III.5 would display the disease O d. Neither III.5 nor V.3 would display the disease Oe. Both III.3 and V.3 would display the disease 10 ન Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual…arrow_forwardIf a genetic disease is inherited as an autosomal recessive, one would expect to find which of the following? A. Two affected individuals never have an unaffected child. B. Two affected individuals have affected male offspring but no affected female children. C. If a child has the disease, one of his or her grandparents will have had it. D. In a marriage between an affected individual and an unaffected one, all the children are unaffected.arrow_forward
- Examination of a karyotype reveals 23 pairs of chromosomes, with each homologous pair illustrating similar size and centromere location. Which of the following can be concluded from this karyotype?a. The individual has Down syndrome.b. The individual is a female.c. The individual does not have cystic fibrosis.d. The individual does not have sickle-cell anemia.arrow_forwardThis is a chromosomal disorder resulting from the non-disjunction of chromosome 21 during anaphase that gives an extra copy of the chromosome to the person who has inherited it.arrow_forwardHow many chromosomes are there in the somatic cells of a newborn boy with: a. The cri-du chat syndrome b. Klinefelter syndrome c. Down syndrome due to a 14/21 Robertsonian translocation d. Triploidy e. Edwards syndromearrow_forward
- a. How would you synthesize a pentaploid?b. How would you synthesize a triploid of genotypeA/a/a?c. You have just obtained a rare recessive mutation a*in a diploid plant, which Mendelian analysis tells you isA/a*. From this plant, how would you synthesize atetraploid (4n) of genotype A/A/a*/a*?d. How would you synthesize a tetraploid of genotypeA/a/a/a?arrow_forwardAn individual with two different alleles at a locus is a(n) Group of answer choices A. clone B. hemizygote C. homozygote D.heterozygotearrow_forwardIn a particular dihybrid (T/t, B/b) the alleles of the "T" and "B"genes indicated in the figure below are located on different chromosomes (blue and red) Which of the choices WOULD NOT represent a stage of MEIOSIS in this organism? B. B. B 8800 B. B. B. E b.arrow_forward
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