Concept explainers
A power plant is driven by the combustion of a complex fossil fuel having the formula C11H7S. Assume the air supply is composed of only N2 and O2 with a molar ratio of 3.76:1.00, and the N2 remains unreacted. In addition to the water produced, the fuel’s C is completely combusted to CO2 and its sulfur content is converted to SO2. In order to evaluate gases emitted at the exhaust stacks for environmental regulation purposes, the nitrogen supplied with the air must also be included in the balanced reactions.
- a Including the N2 supplied m the air, write a balanced combustion equation for the complex fuel assuming 100% stoichiometric combustion (i.e., when there is no excess oxygen in the products and the only C-containing product is CO2). Except in the case of N2, use only integer coefficients.
- b Including N2 supplied in the air, write a balanced combustion equation for the complex fuel assuming 120% stoichiometric combustion (i.e., when excess oxygen is present in the products and the only C-containing product is CO2). Except in the case of use only integer coefficients
- c Calculate the minimum mass (in kg) of air required to completely combust 1700 kg of C11H7S.
- d Calculate the air/fuel mass ratio, assuming 100% stoichiometric combustion.
- e Calculate the air/fuel mass ratio, assuming 120% stoichiometric combustion.
(a)
Interpretation:
The balanced equation for the combustion reaction should be written.
Concept introduction:
Balanced equation:
A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
The equation for a reaction, which has same number of atoms and charge of the ions in both reactants and product sides is known as balanced equation.
Answer to Problem 3.141QP
The balanced equation for the combustion reaction is,
Explanation of Solution
The balance the given combustion reaction.
Given,
Supplied air with ratio is
Products of combustion reaction is
Frist arrange the equation for the combustion reaction is,
Add the 11 coefficient for balancing carbon atom of
Multiply the whole reaction 2 for balancing Hydrogen atom of
Add the 7 coefficient for balancing carbon atom of
In product side has 55 Oxygen atoms so add
Modify the
Add the nu reacted
The balanced equation for the combustion reaction was written.
(b)
Interpretation:
The balanced equation for the
Concept introduction:
Balanced equation:
A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
The equation for a reaction, which has same number of atoms and charge of the ions in both reactants and product sides is known as balanced equation.
Answer to Problem 3.141QP
The balanced equation for the
Explanation of Solution
The balance the given combustion reaction.
Given,
Supplied air with ratio is
Products of combustion reaction is
Frist arrange the equation for the combustion reaction is,
Add the 11 coefficient for balancing carbon atom of
Multiply the whole reaction 2 for balancing Hydrogen atom of
Add the 7 coefficient for balancing carbon atom of
In product side has 55 Oxygen atoms so add
Modify the
Add the nu reacted
For the above
Hence, the above balanced equation,
Simplifying the above equation to give the balanced equation for the balanced equation for the
The balanced equation for the
(c)
Interpretation:
The minimum mass (in kg) of air required to completely combust
Answer to Problem 3.141QP
The minimum mass (in kg) of air required to completely combust
Explanation of Solution
The balance the given combustion reaction.
The balanced equation for given
The mass of are id divided by fuel mass to give an air/fuel mass ratio of
Molar mass of
Molar mass of
Molar mass of
The air/fuel mass ratio of
To calculate the minimum mass (in kg) of air required to completely combust
From the above calculation, the air/fuel mass ratio of
Therefore the air/fuel mass ratio of
The minimum mass (in kg) of air required to completely combust
The minimum mass (in kg) of air required to completely combust
(d)
Interpretation:
The air/fuel mass ratio of
Answer to Problem 3.141QP
The air/fuel mass ratio of
Explanation of Solution
The balance the given combustion reaction.
The balanced equation for given
The mass of are id divided by fuel mass to give an air/fuel mass ratio of
Molar mass of
Molar mass of
Molar mass of
The air/fuel mass ratio of
The masses of air and fuel are plugged above equation to give the air/fuel mass ratio of
The air/fuel mass ratio of
The air/fuel mass ratio of
(e)
Interpretation:
The air/fuel mass ratio of
Answer to Problem 3.141QP
The air/fuel mass ratio of
Explanation of Solution
The balance the given combustion reaction.
The balanced equation for given
The mass of are id divided by fuel mass to give an air/fuel mass ratio of
Molar mass of
Molar mass of
Molar mass of
The air/fuel mass ratio of
The masses of air and fuel are plugged above equation to give the air/fuel mass ratio of
The air/fuel mass ratio of
To calculate the air/fuel mass ratio of
The calculated air/fuel mass ratio of
The air/fuel mass ratio of
The air/fuel mass ratio of
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