Exercises 33 – 38 refer to the graphs of the functions
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Chapter 3 Solutions
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- In Exercises 16–22, show that the two functions are inverses of each other. 2 16. f(x) = 3x + 2 and g(x) = 3arrow_forwardExercises 121–140: (Refer to Examples 12–14.) Complete the following for the given f(x). (a) Find f(x + h). (b) Find the difference quotient of f and simplify. 121. f(x) = 3 122. f(x) = -5 123. f(x) = 2x + 1 124. f(x) = -3x + 4 %3D 125. f(x) = 4x + 3 126. f(x) = 5x – 6 127. f(x) = -6x² - x + 4 128. f(x) = x² + 4x 129. f(x) = 1 – x² 130. f(x) = 3x² 131. f(x) = 132. /(x) 3D글 = = 132. f(: 133. f(x) = 3x² + 1 134. f(x) = x² –- 2 135. f(x) = -x² + 2r 136. f(x) = -4xr² + 1 137. f(x) = 2x - x +1 138. f(x) = x² + 3x - 2 139. f(x) = x' 140. f(x) = 1 – xarrow_forwardIn Exercises 7–10, write a formula for ƒ ∘ g ∘ h. 7. ƒ(x) = x + 1, g(x) = 3x, h(x) = 4 - x 8. ƒ(x) = 3x + 4, g(x) = 2x - 1, h(x) = x2 9. ƒ(x) = sqrt(x + 1), g(x) = 1 /(x+4) , h(x) = 1 /x 10. ƒ(x) = x + 2 /(3 - x) , g(x) = x2 /(x2 + 1) , h(x) = sqrt(2 - x)arrow_forward
- In Exercises 7–10,find the two x-intercepts of the function f andshow that f '(x) = 0 at some point between the twox-intercepts. f (x) = x2 − x − 2arrow_forwardIn Exercises 11–18, graph each function by making a table of coordinates. If applicable, use a graphing utility to confirm your hand-drawn graph. 11. f(x) = 4" 13. g(x) = ()* 15. h(x) = (})* 17. f(x) = (0.6) 12. f(x) = 5" 14. g(x) = () 16. h(x) = (})* 18. f(x) = (0.8)* %3!arrow_forwardExercises 63–86: Use transformations to sketch a graph of f. 63. f(x) = x² – 3 64. f(x) = -x² 65. f(x) = (x = 5)² + 3 66. f(x) = (x + 4)° 67. flx) = -Vx 68. f(x) = 2(x = 1F + 1 69. f(x) = -x² + 4 70. f(x) = V=x 71. f(x) = |x| – 4 73. f(x) = Vx – 3 + 2 74. f(x) = |x + 2| – 3 72. flx) = Vx + 1 76. flx) = |x| 78. f(x) = 2Vx – 2 - 1 75. f(x) = |2x| 77. f(x) = 1 – Vx 79. f(x) = -Vī - x 81. f(x) = V-(x + 1) 80. f(x) = V-x – 1 82. f(x) = 2 + V-(x – 3) 83. f(x) = (x = 1) 84. f(x) = (x + 2) 85. f(x) = -x' 86. f(x) = (-x)' + 1arrow_forward
- In Exercises 69–76, graph each function, not by plotting points, but by starting with the graph of one of the standard functions presented in Figures 1.14–1.17 and applying an appropriate transformation. 69. y = -sqrt(2x + 1) 70. y =sqrt(1-x/2) 71. y = (x - 1)3 + 2 72. y = (1 - x)3 + 2 73. y = 1 /2x - 1 74. y=(2/x2)+1 72. y = (1 - x)3 + 2 75. y = -(x )^(1/3) 76. y = (-2x)^(2/3)arrow_forwardIn Exercises 33–38, express the function, f, in simplified form. Assume that x can be any real number. 33. f(x) = V36(x + 2)² 34. f(x) = V81(x – 2)2 35. f(x) = V32(x + 2)³ 36. f(x) = V48(x – 2)³ 37. f(x) = V3x² – 6x + 3 38. f(x) = V5x2 – 10x + 5 %3Darrow_forward1.2 Let f(x) = 4 + x + x2 and h ≠ 0. Find f(x + h). Find (e) Find f(x+h)-f(x)/h and simplify. part b -f(x) = x − 6x2 and h ≠ 0, find the following and simplify. f(x+h)-(f(x)/harrow_forward
- In Exercises 104–105, express the given function h as a composition of two functions f and g so that h(x) = (f• g)(x). 104. h(x) = (x² + 2x – 1)* 105. h(x) = V7x + 4 %3! %3!arrow_forwardIn Exercises 39–44, each function f(x) changes value when x changes from x, to xo + dx. Find a. the change Af = f(xo + dx) – f(xo); b. the value of the estimate df = f'(xo) dx; and c. the approximation error |Af – df|. y = f(x)/ Af = f(xo + dx) – f(x) df = f'(xo) dx (xo, F(xo)) dx Tangent 0| xo + dx 39. f(x) 3D х? + 2x, хо —D 1, 40. f(x) = 2x² + 4x – 3, xo = -1, dx = 0.1 41. f(x) = x³ - x, xo = 1, dx = 0.1 dx = 0.1 %3D 42. f(x) 3 х, Хо —D 1, dx %3D 0.1 43. f(x) — х 1, Хо —D 0.5, dx %3D0.1 44. f(x) 3D х3 — 2х + 3, Хо — 2, dx 3D 0.1arrow_forwardGraph the functions f(x) = xn for n = 1, 3, and 5 in a [-2, 2, 1] by [-2, 2, 1] viewing rectangle.arrow_forward
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