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Use the principle of super position to determine the power P supplied by
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Principles and Applications of Electrical Engineering
- Using KCL, perform node analysis on the circuitshown in Figure P3.24, and determine the voltageacross R4. Note that one source is a controlled voltagesource! Let VS = 5 V; AV = 70; R1 = 2.2 kΩ;R2 = 1.8 kΩ; R3 = 6.8 kΩ; R4 = 220Ωarrow_forwardA 10-mH inductor has a parasitic series resistance of R s =1 Ω, as shown in FigureP3.68.a. The current is given by i( t )=0.1 cos( 10 5 t ). Find v R ( t ), v L ( t ), and v(t). In thiscase, for 1-percent accuracy in computing v(t), could the resistance be neglected?b. Repeat if i( t )=0.1 cos( 10t ).arrow_forwardIn the circuit given in the figure, Rk = 1.48Kohm, R1 = 7964.99Kohm, R2 = 7035.01Kohm, R3 = 2.46Kohm, R4 = 0.82Kohm, R5 = 24.08ohm, Ry = 98.63Kohm, VCC = 15.00V, VTN = 2.45V, Kn = Since 3.28(mA/V^2), C1= 6.30uF, C2=14.98uF, C3=10.96uF, calculate the lower cutoff frequency of the circuit in Hz.arrow_forward
- In the circuit given in the figure, Rk = 1.48Kohm, R1 = 7964.99Kohm, R2 = 7035.01Kohm, R3 = 2.46Kohm, R4 = 0.82Kohm, R5 = 24.08ohm, Ry = 98.63Kohm, VCC = 15.00V, VTN = 2.45V, Kn = Since 3.28(mA/V^2), C1= 6.30uF, C2=14.98uF, C3=10.96uF, calculate the lower cutoff frequency of the circuit in Hz. When making your transactions, 2 digits will be taken after the dot.arrow_forwardFind the Thévenin equivalent of the circuitconnected to RL in Figure P3.58, where R1 = 10Ω ,R2 = 20 Ω, Rg = 0.1 Ω, and Rp = 1 Ω.arrow_forward3b For the circuit in Figure Q3(b), solve for Ix, Iy and Vz using superposition method.arrow_forward
- Q3:- Design the circuit shown in Fig.(3) , to give a voltage gain = 20 Assume Veso =3V , Vbso =4V, Ing =5 mA and K=2 mA / V? Rin =1 MQ Vop =24Varrow_forward1.What factor(s) can contribute to differences between ideal theoretical values in a circuit and values measured in actual practice? A) Measurement inaccuracy B)Component tolerances C)Both (a) and (b). D)Neither (a) nor (b). 2.What maximum range of values could resistor R3 have and still be within tolerance assuming R3 is a 10% resistor? A) 3296.7 – 3303.3 Ω B) 2970 – 3630 Ω C) 3267 – 3333 Ω D) 2967 – 3633 Ω 3.A voltage of one volt applied across a resistance of one ohm produces a current of one ampere. What happens to the current if the voltage is doubled and the resistance is halve? A)It doubles. B)It increases four times. C)It increases three times. D)It remains the same. In Question 3, what is the current in amperes if the voltage is halved and the resistance is doubled? A) 1 ampere B) 33 ampere C) 5 ampere D) 25 amperearrow_forwardIn the circuit shown in Figure P3.33, F1 and F2 arefuses. Under normal conditions they are modeled as ashort circuit. However, if excess current flows througha fuse, it “blows” and the fuse becomes an open circuit.VS1 = VS2 = 120 VR1 = R2 = 2 Ω R3 = 8Ω R4 = R5 = 250 mΩIf F1 blows, or opens, determine, using KCL and nodeanalysis, the voltages across R1, R2, R3, and F1.arrow_forward
- find Rt, It, Pt, P1, P2, P3P4,P5,P6arrow_forward5- self inductorQ3-A current source of 3 mA has an internal resistance of 5 MΩ. Over what range of load resistance is the current source stiff? Plot the diagram and circuit.arrow_forwardThe system shown in Figure Q3(a) is modified and the new block diagram of thesystem is as shown in Figure Q3(b). Given that the value of K = 100 and the systemhas been tested with three different reference inputs, which are 5 u(t), 5t u(t) and 5t^2u(t). Based on Figure Q3(b) and by using steady state error analysis, calculate whichcould give infinite steady state error.arrow_forward
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