Concept explainers
Find the Thé’cnin equivalent resistance seen by
The Thevenin equivalent resistance seen by
Answer to Problem 3.65HP
The Thevenin equivalent resistance seen by the resistance
Explanation of Solution
Calculation:
The given diagram is shown in Figure 1
To calculate the Thevenin resistance, open circuit current source and short circuit the voltage source, the redraw the circuit.
The required diagram is shown in Figure 2
From above the equivalent resistance of the circuit is evaluated as,
Mark the values and redraw the given circuit.
The required diagram is shown in Figure 3
From the above figure the node voltage
The expression for the voltage
Apply KVL at node
Subsitue
Substitute
Substitute
Apply KVL to the node
Substitute
To obtain the equivalent Thevenin resistance of the circuit open circuit the load terminals, short circuit the voltage source and redraw the circuit.
The required diagram is shown in Figure 4
From the above circuit, the equivalent resistance is calculated as,
To obtain the Thevenin equivalent voltage between the terminals, open circuit the load terminals and redraw the circuit.
The required diagram is shown in Figure 5
From the above circuit, the node voltage
The current through the resistance of
From above circuit, the node voltage
Substitute
The expression to calculate the Thevenin equivalent voltage is given by,
Substitute
The expression to calculate the Norton equivalent current is given by,
Substitute
Conclusion:
Therefore, the Thevenin equivalent resistance seen by the resistance
Want to see more full solutions like this?
Chapter 3 Solutions
Principles and Applications of Electrical Engineering
- A nonideal voltage source is modeled in FigureP3.72 as an ideal source in series with a resistance thatmodels the internal losses, that is, dissipates the samepower as the internal losses. In the circuit shown inFigure P3.72, with the load resistor removed so thatthe current is zero (i.e., no load), the terminal voltageof the source is measured and is 20 V. Then, withRL = 2.7 kΩ, the terminal voltage is again measuredand is now 18 V. Determine the internal resistance andthe voltage of the ideal source.arrow_forwardUsing KCL, perform node analysis on the circuitshown in Figure P3.24, and determine the voltageacross R4. Note that one source is a controlled voltagesource! Let VS = 5 V; AV = 70; R1 = 2.2 kΩ;R2 = 1.8 kΩ; R3 = 6.8 kΩ; R4 = 220Ωarrow_forwardUsing mesh current analysis, find the currents i1 and i2 for the circuit of Figure P3.14.arrow_forward
- The circuit shown in Figure P3.35 is a simplifiedDC version of an AC three-phase electrical distributionsystem.VS1 = VS2 = VS3 = 170 VRW1 = RW2 = RW3 = 0.7Ω R1 = 1.9Ω R2 = 2.3Ω R3 = 11 ΩTo prove how cumbersome and inefficient (althoughsometimes necessary) the method is, determine, usingsuperposition, the current through R1.arrow_forwardFind the voltage v across the 3- resistor in thecircuit of Figure P3.52 by replacing the remainder ofthe circuit with its Thévenin equivalentarrow_forwardThe circuit shown in Figure P3.35 is a simplifiedDC version of a typical three-wire, three-phase ACY-Y distribution system.Write the mesh (or loop)equations and any additional equations required todetermine the current through R1 in the circuit shown.arrow_forward
- Determine the value of ZL in the circuit of Figure Q3(a) for maximum power transfer.arrow_forwardUsing mesh current analysis, find the voltage gainAv = v2/v1 in the circuit of Figure P3.31.arrow_forwardFor the circuit of Figure P3.22 determinea. The most efficient way to solve for the voltageacross R3. Prove your case.b. The voltage across R3.VS1 = VS2 = 110 VR1 = 500 m R2 = 167 mR3 = 700 mR4 = 200 m R5 = 333 marrow_forward
- Using node voltage analysis, find the voltages V1 and V2 for the circuit of Figure P3.2.arrow_forwardIn the circuit shown in Figure P3.33, F1 and F2 arefuses. Under normal conditions they are modeled as ashort circuit. However, if excess current flows througha fuse, it “blows” and the fuse becomes an open circuit.VS1 = VS2 = 120 VR1 = R2 = 2 Ω R3 = 8Ω R4 = R5 = 250 mΩIf F1 blows, or opens, determine, using KCL and nodeanalysis, the voltages across R1, R2, R3, and F1.arrow_forwardcan someone show me step by step how to do this problem and explain the concepts A device, shown in Figure P3.5a, can be modeled by a current source in parallel with a resistance. The relationship between the current through the device, iX, and the voltage across the device, vX, is given in the plot in Figure P3.5b. a) Find a model for the device that would be valid when current is in the range 1[mA] < iX < 5[mA]. This model must have numerical values for the current and resistance, and the polarities with respect to vX and iX should be shown in a diagram. b) A voltage source is applied across the device so that vX = 10[V]. Find the power delivered by the device in this situation.arrow_forward
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,