A book slides off a horizontal tabletop. As it leaves the table’s edge, the book has a horizontal velocity of magnitude v 0 . The book strikes the floor in time t . If the initial velocity of the book is doubled to 2 v 0 , what happens to (a) the time the book is in the air, (b) the horizontal distance the book travels while it is in the air, and (c) the speed of the book just before it reaches the floor? In particular, does each of these quantities stay the same, double, or change in another way? Explain.
A book slides off a horizontal tabletop. As it leaves the table’s edge, the book has a horizontal velocity of magnitude v 0 . The book strikes the floor in time t . If the initial velocity of the book is doubled to 2 v 0 , what happens to (a) the time the book is in the air, (b) the horizontal distance the book travels while it is in the air, and (c) the speed of the book just before it reaches the floor? In particular, does each of these quantities stay the same, double, or change in another way? Explain.
A book slides off a horizontal tabletop. As it leaves the table’s edge, the book has a horizontal velocity of magnitude v0. The book strikes the floor in time t. If the initial velocity of the book is doubled to 2v0, what happens to (a) the time the book is in the air, (b) the horizontal distance the book travels while it is in the air, and (c) the speed of the book just before it reaches the floor? In particular, does each of these quantities stay the same, double, or change in another way? Explain.
A marble is launched from the edge of a table at a angle of 45 ° up from horizontal and goes through the air until it hits the floor. True or False? For such a marble, |vx| (the magnitude of the x-component of the velocity) is decreasing the entire time the marble is airborne.
A football is placed at rest on the field with initial coordinates x0 = 0 and y0 = 0. The ball is then kicked and thereby given an initial velocity of magnitude v0 = 23.6 m/s and direction θ0 = 36.3o above the horizontal. Ignore the effects of air resistance.
Initial horizontal component of the velocity v0x =
Initial vertical component of the velocity v0y =
Horizontal component of the acceleration ax =
Vertical component of the acceleration ay =
Enter the equation for the horizontal position versus time, x(t) =
Enter the equation for the vertical position versus time, y(t) =
Enter the equation for the horizontal velocity versus time, vx(t) =
Enter the equation for the vertical velocity versus time, vy(t) =
Enter the equation for the total velocity versus time, v(t) =
Enter the equation for the angle of the velocity vector versus time, θ(t)=
Enter the maximum height of the football
Enter the range of the football
Enter the time it takes for the football to reach its maximum…
A cannon ball is fired with an initial speed of 123 m/s at angle of 60 degrees from the horizontal.
Express the initial velocity as a linear combination of its unit vector components.
( m/s) + ( m/s)
At the maximum height, the speed of the cannon ball is v = ? m/s and the magnitude of its acceleration is a = ? m/s2.
The time needed to reach maximum height is t = ? s.
The maximum height reached by the cannon ball is H = ? m.
Chapter 3 Solutions
University Physics with Modern Physics (14th Edition)
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