Chapter 3, Problem 3.62P

Interpretation Introduction

Interpretation:

To find the pressure in size D cylinder volume $\text{2}\text{.40}\text{liters }$ contains phosphine $P{H}_3$ of mass $454\text{g}$ at ${\text{20}}^{\text{o}}\text{C}$ .

Concept Introduction:

The molar volume of phosphine in cylinder is given as:

  $V=\frac{V_{total}}{n}$

The mass of phosphene in cylinder is:

  $\begin{array}{l}m=n\times M\\ m=\frac{V_{total}}{V}\times M\end{array}$

Where $n$ is number of moles of phosphine present in cylinder, $M$ is molecular weight of phosphine.

The $V$ is molar volume and $V_{total}$ is total volume of tank.

The molar volume of phosphine in cylinderis also calculated from generalized correlations for gases given by Pitzer at given conditions. The expression is:

  $Z=1+B^0\frac{P_r}{T_r}+\omega B^1\frac{P_r}{T_r}$ where $PV=ZRT$......(1)