Chapter 3, Problem 39E

a.

Explanation of Solution

The values of “A10” and “WE”:

• The first memory location is denoted as “00”.
• The second memory location is denoted as “01”.
• The third memory location is denoted as “10”.
• The fourth memory location is denoted as “11”.
• The input can be taken from “A10” by the address decoder. It declares one of the output values to each line of word, which is to be addressed...

b.

Explanation of Solution

Required number of address lines to change the number of entries:

The number of address lines needed to modify the number of entries from “4” to “60” is “6”.

Explanation:

• The number of memory locations for “4” address lines is “$2^4$”, which means “16”.
• The number of memory locations for “5” address lines is “$2^5$”, which means “32”

c.

Explanation of Solution

Number of additional memory locations:

• Given that the least number of bits required to address all “60” locations is considered as the width of the program counter.
• With “6” bits, “$2^6$” which means “64” locations can be addressed