Atkins' Physical Chemistry
Atkins' Physical Chemistry
11th Edition
ISBN: 9780198769866
Author: ATKINS, P. W. (peter William), De Paula, Julio, Keeler, JAMES
Publisher: Oxford University Press
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Chapter 3, Problem 3A.1ST
Interpretation Introduction

Interpretation: The change in entropy when the pressure of a fixed amount of perfect gas is changed isothermally from pi to pf has to be calculated.  The origin of this change has to be stated.

Concept introduction: The degree of disorder or randomness is measured in term of entropy. According to thermodynamic definition, entropy is defined as the ratio of thermal energy to absolute temperature.

Expert Solution & Answer
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Answer to Problem 3A.1ST

The change in entropy when the pressure of a fixed amount of perfect gas for nmole is changed isothermally from pi to pf is calculated as,

  ΔS=nRlnPiPf

Explanation of Solution

The thermodynamic definition of entropy is expressed by formula,

  dS=dqrevT                                                                                                    (1)

Where,

  • dS is the entropy change.
  • dqrev is the energy transfer at absolute temperature T.

Rearrange the above equation (1).

  dqrev=TdS

From the first law of thermodynamics,

  dU=dqdW                                                                                             (2)

Where,

  • dU is the change in internal energy at constant volume.
  • dW is the work done.
  • • The change in internal energy at constant volume is expressed by the formula,

    dU=CVdT (3)

The work done is expressed as,

  dW=Pdv (4)

Substitute the values of dqrev, dU and dW in equation (2).

  dU=dqdWdq=dU+dWTdS=CvdT+Pdv

Here the process is isothermal.  It means that the temperature is constant.  Therefore, at constant temperature, dT=0 and the term, CVdT=0.

Substitute, CVdT=0 in the above equation.

  TdS=CvdT+PdvTdS=0+PdvTdS=PdvdS=PdvT

Simplify the above equation.

  T=PdvdS

From the ideal gas equation,

  PV=nRTT=PVnR

Substitute the value of T in the above expression.

  T=PVnRPdvdS=PVnRdS=nRdvV

Integrate the above derivative between two states, initial and final, i and f respectively.

  sisfdS=vivfnRdvVsisfdS=nRvivfdvVsfsi=nRln(VfVi)ΔS=nRln(VfVi)

From ideal gas equation,

  PV=nRT

At constant temperature,

PV will also be constant.  Therefore, it can be also written as,

  PiVi=PfVfPiPf=VfVi

Replace VfVi by PiPf in the above expression.

  ΔS=nRln(PiPf)

Hence, the entropy change when the pressure of a fixed amount of perfect gas is changed isothermally from pi to pf is shown by the expression,

  ΔS=nRln(PiPf)

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Chapter 3 Solutions

Atkins' Physical Chemistry

Ch. 3 - Prob. 3A.1AECh. 3 - Prob. 3A.1BECh. 3 - Prob. 3A.2AECh. 3 - Prob. 3A.2BECh. 3 - Prob. 3A.3AECh. 3 - Prob. 3A.3BECh. 3 - Prob. 3A.4AECh. 3 - Prob. 3A.4BECh. 3 - Prob. 3A.5AECh. 3 - Prob. 3A.5BECh. 3 - Prob. 3A.6AECh. 3 - Prob. 3A.6BECh. 3 - Prob. 3A.1PCh. 3 - Prob. 3A.2PCh. 3 - Prob. 3A.3PCh. 3 - Prob. 3A.4PCh. 3 - Prob. 3A.5PCh. 3 - Prob. 3A.6PCh. 3 - Prob. 3A.7PCh. 3 - Prob. 3B.1DQCh. 3 - Prob. 3B.1AECh. 3 - Prob. 3B.1BECh. 3 - Prob. 3B.2AECh. 3 - Prob. 3B.2BECh. 3 - Prob. 3B.3AECh. 3 - Prob. 3B.3BECh. 3 - Prob. 3B.4AECh. 3 - Prob. 3B.4BECh. 3 - Prob. 3B.5AECh. 3 - Prob. 3B.5BECh. 3 - Prob. 3B.6AECh. 3 - Prob. 3B.6BECh. 3 - Prob. 3B.7AECh. 3 - Prob. 3B.7BECh. 3 - Prob. 3B.1PCh. 3 - Prob. 3B.2PCh. 3 - Prob. 3B.3PCh. 3 - Prob. 3B.4PCh. 3 - Prob. 3B.5PCh. 3 - Prob. 3B.6PCh. 3 - Prob. 3B.7PCh. 3 - Prob. 3B.8PCh. 3 - Prob. 3B.9PCh. 3 - Prob. 3B.10PCh. 3 - Prob. 3B.12PCh. 3 - Prob. 3C.1DQCh. 3 - Prob. 3C.1AECh. 3 - Prob. 3C.1BECh. 3 - Prob. 3C.2AECh. 3 - Prob. 3C.2BECh. 3 - Prob. 3C.3AECh. 3 - Prob. 3C.3BECh. 3 - Prob. 3C.1PCh. 3 - Prob. 3C.2PCh. 3 - Prob. 3C.4PCh. 3 - Prob. 3C.5PCh. 3 - Prob. 3C.6PCh. 3 - Prob. 3C.7PCh. 3 - Prob. 3C.8PCh. 3 - Prob. 3C.9PCh. 3 - Prob. 3C.10PCh. 3 - Prob. 3D.1DQCh. 3 - Prob. 3D.2DQCh. 3 - Prob. 3D.1AECh. 3 - Prob. 3D.1BECh. 3 - Prob. 3D.2AECh. 3 - Prob. 3D.2BECh. 3 - Prob. 3D.3AECh. 3 - Prob. 3D.3BECh. 3 - Prob. 3D.4AECh. 3 - Prob. 3D.4BECh. 3 - Prob. 3D.5AECh. 3 - Prob. 3D.5BECh. 3 - Prob. 3D.1PCh. 3 - Prob. 3D.2PCh. 3 - Prob. 3D.3PCh. 3 - Prob. 3D.4PCh. 3 - Prob. 3D.5PCh. 3 - Prob. 3D.6PCh. 3 - Prob. 3E.1DQCh. 3 - Prob. 3E.2DQCh. 3 - Prob. 3E.1AECh. 3 - Prob. 3E.1BECh. 3 - Prob. 3E.2AECh. 3 - Prob. 3E.2BECh. 3 - Prob. 3E.3AECh. 3 - Prob. 3E.3BECh. 3 - Prob. 3E.4AECh. 3 - Prob. 3E.4BECh. 3 - Prob. 3E.5AECh. 3 - Prob. 3E.5BECh. 3 - Prob. 3E.6AECh. 3 - Prob. 3E.6BECh. 3 - Prob. 3E.1PCh. 3 - Prob. 3E.2PCh. 3 - Prob. 3E.3PCh. 3 - Prob. 3E.4PCh. 3 - Prob. 3E.5PCh. 3 - Prob. 3E.6PCh. 3 - Prob. 3E.8PCh. 3 - Prob. 3.1IACh. 3 - Prob. 3.2IA
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