21st Century Astronomy
21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
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Chapter 3, Problem 6QP
To determine

What happens while the elliptical moving planet is closer to the star and far away.

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Neptune orbits the Sun with an orbital radius of 4.495 x 10^12 m. If the earth to sun distance 1A.U. = 1.5 x 10^11 m, a) Determine how many A.U.'s is Neptune's orbital radius (Round to the nearest tenth). b) Given the Sun's mass is 1.99 x10^30 kg, use Newton's modified version of Kepler's formula T^2 = (4pi^2/Gm(star)) x d^3 to find the period in seconds using scientific notation. (Round to the nearest thousandth). C) Convert the period in part b) to years (Round to the nearest tenth)
A planet with 20 times the earth's mass and 3 times its radius exists. It orbits a star with twice the sun's mass with a circular orbit of radius 18 AU where 1 AU is the earth sun distance.1. What is the period of the planet's orbit in years? 2. Suppose something weighs 1600 books (books is a unit of mass) on that planet, what is it weight on earth in books?
A planet in a circular orbit about a star has an orbital radius of 3.70 au . If the star has a mass that is 1.80 times our own Sun's mass, determine the time ? , in units of Earth years, for one revolution of the planet around the star.T = ? Earth years
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Kepler's Three Laws Explained; Author: PhysicsHigh;https://www.youtube.com/watch?v=kyR6EO_RMKE;License: Standard YouTube License, CC-BY