Explanation Given information : The velocity of particle changes from 1,200 m/s to 6,000 m/s in 2×1 0 -3 seconds. Formula used : The rate of change of velocity is known as the acceleration of the particle. Calculations: The acceleration of a particle change in its velocity d v (m/s) occurs in time d t (seconds) is given by Acceleration = d v d t ......(1) The velocity of particle changes from 1,200 m/s to 6,000 m/s in 2×1 0 -3 seconds. Thus, d v = v 2 - v 1 =6,000m/s - 1,200m/s=4,800m/s , and d t =2×1 0 -3 seconds

Student's Solution and Survival Manual for Calculus

7th Edition

ISBN: 9781524934040

Author: STRAUSS MONTY J, TODA MAGDALENA DANIELE, SMITH KARL J

Publisher: Kendall Hunt Publishing

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Chapter 3, Problem 83SP

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Tofind:Theaccelerationofparticle projected into an accelerator.

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Chapter 3, Problem 82SP

Chapter 3, Problem 84SP

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Chapter 3 Solutions

Student's Solution and Survival Manual for Calculus

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Tofind: Theaccelerationofparticle projected into an accelerator.

Solution Summary: The author describes the acceleration of a particle projected into an accelerator.

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