Explanation Given information: The given thermal expansion is σ = L ′ ( T ) L ( T ) Where T is temperature, L ( T ) is length, σ = 1.4 × 10 − 5 Calculation: Given equation is σ = L ′ ( T ) L ( T ) σ ⋅ d T = d L L Integrate on both sides ∫ σ ⋅ d T = ∫ d L L σ T = log ( L ) L = e σ T + C ..................................... ( 1 ) There are two cases here L 1 = e 1.4 × 10 − 5 × ( − 10 ) + C

Student's Solution and Survival Manual for Calculus

7th Edition

ISBN: 9781524934040

Author: STRAUSS MONTY J, TODA MAGDALENA DANIELE, SMITH KARL J

Publisher: Kendall Hunt Publishing

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Chapter 3.8, Problem 39PS

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To find: how much will the length change during a year when the temperature varies from −10°C in winter to 40°C in summer.

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Chapter 3.8, Problem 38PS

Chapter 3.8, Problem 40PS

Chapter 3 Solutions

Student's Solution and Survival Manual for Calculus

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how much will the length change during a year when the temperature varies from − 10 ° C in winter to 40 ° C in summer.

Solution Summary: The author calculates how much the length changes during a year when the temperature varies from -10°C in winter to 40°

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To find: how much will the length change during a year when the temperature varies from −10°C in winter to 40°C in summer.

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Chapter 3 Solutions