Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
12th Edition
ISBN: 9781259587399
Author: Eugene Hecht
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Question
Chapter 30, Problem 22SP
To determine
The speed of the ions that pass undeflected through crossed electric field of magnitude
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
If a proton and electron are released when they are 2.0 m apart, find the initial acceleration of the electron (in m/s2).
The answer (in fundamental SI unit) is ___________ (type the numeric value only)
Assuming the radius of the circular path of the electron is 4.9cm when voltage is 100v and coil current is 1.4 A and The Helmholtz coils have 130 turns and a radius of 15 cm. With N=130 and R=0.15
If the current in the Helmholtz coils were 1.4 A, rather than 1 A, and the accelerating voltage were still 100 V, what would the radius of the electron's path be? Give your answer in cm, and enter only the number. Blackboard will accept an answer witin 20% of the value it expects.
An alpha particle with velocity v = (3 x 105,0,0) m/s enters a region where themagnetic field has a value B = (0,0,1.2) T. Determine the required magnitude and directionof an electric field E that will allow the alpha particle to continue to move along the x axis.
Chapter 30 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
Ch. 30 - 30.14 [I] A proton travels at 100 m/s in and...Ch. 30 - 30.15 [I] A proton travels at 100 m/s in and...Ch. 30 - 30.16 [I] A minute conducting sphere carrying ...Ch. 30 - 30.17 [I] An ion enters a magnetic field of 1.2 ...Ch. 30 - 30.18 [I] A proton is traveling at 200 m/s in the...Ch. 30 - 30.19 [I] A proton is traveling at 200 m/s in the...Ch. 30 - 30.20 [I] A proton is traveling at 400 m/s in the...Ch. 30 - 30.21 [I] An electron is traveling at 4.00 km/s in...Ch. 30 - Prob. 22SPCh. 30 - Prob. 23SP
Ch. 30 - Prob. 24SPCh. 30 - Prob. 25SPCh. 30 - Prob. 26SPCh. 30 - Prob. 27SPCh. 30 - 30.28 [I] Imagine a length of straight wire 40.0...Ch. 30 - Prob. 29SPCh. 30 - 30.30 [I] A 300-cm-long piece of straight wire is...Ch. 30 - 30.31 [I] A straight wire 15 cm long, carrying a...Ch. 30 - Prob. 32SPCh. 30 - Prob. 33SPCh. 30 - 30.34 [II] A flat rectangular coil of 25 loops is...Ch. 30 - 30.35 [II] An electron is accelerated from rest...Ch. 30 - 30.36 [II] A proton and a deuteron are both...
Knowledge Booster
Similar questions
- A proton precesses with a frequency p in the presence of a magnetic field. If the intensity of the magnetic field is doubled, what happens to the precessional frequency?arrow_forwardWhat is the radius of curvature of the path of a 3.0-keV proton in a perpendicular magnetic field of magnitude 0.80 T?arrow_forwardAn electron in J. J. Thomson's charge-to-mass apparatus moves perpendicular to a B-field along a circular path of radius 13.10 cm. If imposition of an E-field of 17.80 kV/m makes the path straight, what is the value of B?arrow_forward
- A 0.50 T magnetic field is applied to a paramagnetic gas whose atoms have an intrinsic magnetic dipole moment of 1.0* 10^23 J/T. At what temperature will the mean kinetic energy of translation of the atoms equal the energy required to reverse such a dipole end for end in this magnetic field?arrow_forwardIn the figure, an electron accelerated from rest through potential difference V1=1.26 kV enters the gap between two parallel plates having separation d = 19.6 mm and potential difference V2= 52.4 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? I need this in units of mT.arrow_forwardWhat is the speed of a beam of electrons (in SI units) that go undeflected when passing through crossed electric and magnetic fields of magnitude (5.07x10^0)x104 V/m and (4.270x10^0)x10-3 T, respectively? Give your answer to 3 sf.arrow_forward
- an electron accelerated from rest through potential difference V1 1.00 kV enters the gap between two parallel plates having separation d =20.0 mm and potential difference V2 =100 V.The lower plate is at the lower potential. Neglect fringing and assume that the electron’s velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap?arrow_forwardIn the figure, an electron accelerated from rest through potential difference V1=1.26 kV enters the gap between two parallel plates having separation d = 19.6 mm and potential difference V2= 52.4 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap?arrow_forwardCompute the resonance frequency of free protons in a magnetic field of (a) 0.5 × 10-4T (the approximate strength of Earth's field), (b) 0.25 T, and (c) 0.5 T.arrow_forward
- The exchange coupling as being responsible for ferromagnetism is not the mutual magnetic interaction between two elementary magnetic dipoles. To show this, calculate (a) the magnitude of the magnetic field a distance of 11 nm away, along a dipole axis, from an atom with magnetic dipole moment 1.9 × 10-23 J/T, and (b) the minimum energy required to turn a second identical dipole end for end in this field.arrow_forwardThe exchange coupling mentioned in Module 32-8 as being responsible for ferromagnetism is not the mutual magnetic interaction between two elementary magnetic dipoles. To show this, calculate (a) the magnitude of the magnetic field a distance of 10 nm away, along the dipole axis, from an atom with magnetic dipole moment 1.5 * 10-23 J/T (cobalt), and (b) the minimum energy required to turn a second identical dipole end for end in this field. (c) By comparing the latter with the mean translational kinetic energy of 0.040 eV, what can you conclude?arrow_forwardWhat is the velocity of a beam of electrons that go undeflected when passing through crossed (perpendicular) electric and magnetic fields of magnitude 1.93×104 V/m and 2.50×10-3T, respectively? me=9.11×10-31kg, e=1.60×10-19 C.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning