Explanation 1) Concept: We will use Faradays law of electromagnetic induction with Lenz law. The loop is moving in a uniform magnetic field so it experiences a force due to applied magnetic field. This force must be balanced by the weight of the loop to achieve terminal velocity. 2) Formula: i) Flux of magnetic field through closed loop, ϕ B = ∮ B → · d s → ii) e.m.f induced in the loop, ϵ i n d = - d ϕ B d t iii) Force acting on the current loop kept in magnetic field is, F → = i d l → × B → 3) Given: i) Width of conducting loop, L ii) Resistance of the loop, R iii) Mass of the loop, m iv) Uniform magnetic field going into the plane of paper, B → 4) Calculations: When the loop attains terminal velocity, its acceleration is zero. Therefore, forces acting on the loop are balanced. Therefore, we have F → = i d l → × B → = i L - i ^ × B - k ^ = i L B j ^ = m g j ^ We assume y-axis to be parallel to the sides of the loop and x-axis to be parallel to the width of the loop

10th Edition

ISBN: 9781119164333

Author: Halliday

Publisher: WILEY

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Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

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Chapter 30, Problem 34P

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Expression of for vt

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Chapter 30, Problem 33P

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A circular loop is at rest in a uniform magnetic field B of magnitude 10.8 mT that is directed to the right. The loop has a radius of 30 millimeters, and it is rotated 31.6 degrees from the B-field, as shown above. The total magnetic flux through the loop is ΦB =_______________T*m2

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Expression of for v t

Solution Summary: The author uses Faraday's law of electromagnetic induction with Lenz law. The loop experiences a force due to applied magnetic field.

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To find:

Expression of for vt

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Chapter 30 Solutions

Expression of for v t

Solution Summary: The author uses Faraday's law of electromagnetic induction with Lenz law. The loop experiences a force due to applied magnetic field.

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To find: Expression of for vt

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Chapter 30 Solutions

To find:

Expression of for vt