Concept explainers
Consider the Tesla coil described in Example 30.1. If you make the solenoid out of twice as much wire, so that it has twice as many turns and is twice as long, how much larger is the mutual inductance? (i) M is four times greater; (ii) M is twice as great; (iii) M is unchanged; (iv) M is
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- Suppose that a cylindrical solenoid is wrapped around a core of iron whose magnetic susceptibility is x. Using Equation 14.9, show that the self-inductance of the solenoid is given by L=(l+x)+0n2Al where l is its length, A its cross-sectional area and N its total number of turns. Nm=Uarrow_forwardConsider a 23 mH inductor that has a resistance of 4.15 Ω. Time constant is 0.00554. If the inductor is connected to a 12.0 V battery, what is the current, I, in amperes, after 12.5 ms?arrow_forwardSuppose a 0.3 m long solenoid with cross-sectional area of 12 cm 2, N 1 = 1400 turns and N 2 = 20 turns, produces a mutual inductance 'M'. Now if there are two inductors namely 0.1 H and 350 mH are connected in parallel. Effectively having opposing magnetic fields which results to a mutual inductance. Use the value of 'M' to calculate the overall inductance of the parallel combination.Choices:0.0987 H0.0777 H 0.0389 H 0.1555 Harrow_forward
- An LR circuit is hooked up to a battery which the switch initially open. The resistance in the circuit is R = 110 Ohm, the inductance is L=4.80H, and battery maintains a voltage of E=47.0V. At time t=0 the switch is closed. What is the current through the circuit after the switch has been closed for t=2.66 times 10-2s? What is the voltage across the inductor after the switch has been closed for t=2.66 times 10-2 seconds?arrow_forwardAn electric current flows through a solenoid that increases from 0.2 A to 1.7 A in a time interval of 0.3 s. Assuming that the inductance of the solenoid is equal to L = 4 mH and that the electric current increases linearly, what is the induced emf between the ends of the solenoid? Possible answers:• a) 10mV• b) 15mV• c) 20mV• d) 25mV• e) 30mV( NO GPT PLEASE,NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE ).arrow_forward30.29 In Fig. 30.11, switch S1 is closed while switch S2 is kept open. The inductance is L = 0.380 H, the resistance is 48 Ohms, and the emf of the battery is 18 V. At time t after S1 is closed, the current in the circuit is increasing at a rate of di/dt = 7.2 A/s. At this instant, what is Vab, the voltage across the resistor?arrow_forward
- Calculate the current flowing in a 50 mH - inductor if the energy stored in its magnetic field is 280 µJ. A.0.10583 A B. 0.3347 A C. 3.3466 A D. 0.0112 Aarrow_forwardSuppose a 0.3 m long solenoid with cross-sectional area of 12 cm 2, N 1 = 1400 turns and N 2 = 20 turns, produces a mutual inductance 'M'. Now if there are two inductors namely 0.1 H and 350 mH are connected in parallel. Effectively having opposing magnetic fields which results to a mutual inductance. Use the value of 'M' to calculate the overall inductance of the parallel combination. A. 0.0389 H B. 0.0987 H C. 0.0777 H D. 0.1555 Harrow_forwardY&F 30.30 | Consider the circuit in Exercise 30.21(An inductor with an inductance of 2.50 H and a resistance of 8.00Ω is connected to the terminals of a battery with an emf of 6.00 V and negligible internal resistance.) (a) Just after the circuit is completed, at what rate is the battery supplying electrical energy to the circuit? (b) When the current has reached its final steady-state value, how much energy is stored in the inductor? What is the rate at which electrical energy is being dissipated in the resistance of the inductor? What is the rate at which the battery is supplying electrical energy to the circuit?arrow_forward
- At time t = 0, a 12.0 V potential difference is suddenly applied to the leads of a coil of inductance 23.0 mH and a certain resistance R. At time t = 0.150 ms, the current through the inductor is changing at the rate of 280 A/s. Evaluate R.arrow_forwardThe current I flowing rightward through inductor L is at a steady rate of 0.1280 A/s. The magnitude I εL I of the difference between the right end and the left end of the inductor is 0.0160 (V). What is the inductance L? Which end of the inductor above is at higher voltage, the left end or the right end? Explain.arrow_forwardA 6.0 V battery has been connected to an LR circuit for sufficient time so that a steady current flows through the resistor R=2.2kΩ and inductor L=18mH. At t=0, the battery is removed from the circuit and the current decays exponentially through R. Write the equation for the emf across the inductor as a function of time t. At what time is the emf greatest?arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning