Explanation When an object enters the magnetic field, an eddy current is produced in the anticlockwise direction inside the object and when the object leaves a magnetic field eddy current is produced in clockwise inside the object. In this case, an aluminum sheet is oscillating between two magnetic poles. Therefore, when the aluminum sheet enters the magnetic pole, an eddy current is produced in the anticlockwise direction inside the aluminum sheet, and when the aluminum sheet leaves the magnetic pole, an eddy current is produced in the clockwise direction inside the aluminum sheet. Therefore, due to oscillation, an eddy current is produced in both clockwise and anticlockwise inside the aluminum sheet alternatively. During clockwise flow of eddy current, a magnetic field comes from one face of the sheet, and during the anticlockwise flow of eddy current, a magnetic field comes from another face of the sheet...

Physics for Scientists and Engineers with Modern Physics, Technology Update

9th Edition

ISBN: 9781305401969

Author: SERWAY, Raymond A.; Jewett, John W.

Publisher: Cengage Learning

See similar textbooks

Videos

Question

Chapter 31.6, Problem 31.5QQ

To determine

The reason for oscillation decay.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 31.5, Problem 31.4QQ

Chapter 31, Problem 1OQ

Students have asked these similar questions

A piece of wire is bent to form a circle with radius r. It has a steady current I flowing through it in a counterclockwise direction as seen from the top (looking in the negative z direction). What is Bz(0), the z component of at the center (i.e., x=y=z=0) of the loop?

A 150-kg electromagnet is at rest and is holding 100 kg of scrap steel when the current is turned off and the steel is dropped. Knowing that the cable and the supporting crane have a total stiffness equivalent to a spring of constant 200 kN/m, determine (a) the frequency, the amplitude, and the maximum velocity of the resulting motion, (b) the minimum tension that will occur in the cable during the motion, (c) the velocity of the magnet 0.03 s after the current is turned off.

A 0.5m long straight conductor wire placed on the z-axis carries a current of 10A. If B=-r0,1T in the region where the conductor is located, find the amplitude of the force on the conductor.

Chapter 31 Solutions

Physics for Scientists and Engineers with Modern Physics, Technology Update

Ch. 31.1 - A circular loop of wire is held in a uniform...Ch. 31.2 - QUICK QUIZ 30.2 In Figure 30.8a, a given applied...Ch. 31.3 - Figure 30.12 (Quick Quiz 30.3) QUICK QUIZ 30.3...Ch. 31.5 - Prob. 31.4QQ Ch. 31.6 - Prob. 31.5QQ Ch. 31 - Prob. 1OQ Ch. 31 - Prob. 2OQ Ch. 31 - Prob. 3OQ Ch. 31 - Prob. 4OQ Ch. 31 - Prob. 5OQ

Ch. 31 - Prob. 6OQ Ch. 31 - Prob. 7OQ Ch. 31 - Prob. 8OQ Ch. 31 - Prob. 9OQ Ch. 31 - Prob. 10OQ Ch. 31 - Prob. 11OQ Ch. 31 - Prob. 1CQ Ch. 31 - Prob. 2CQ Ch. 31 - Prob. 3CQ Ch. 31 - Prob. 4CQ Ch. 31 - Prob. 5CQ Ch. 31 - Prob. 6CQ Ch. 31 - Prob. 7CQ Ch. 31 - Prob. 8CQ Ch. 31 - Prob. 9CQ Ch. 31 - Prob. 10CQ Ch. 31 - Prob. 1P Ch. 31 - Prob. 2P Ch. 31 - Prob. 3P Ch. 31 - Prob. 4P Ch. 31 - Prob. 5P Ch. 31 - Prob. 6P Ch. 31 - Prob. 7P Ch. 31 - Prob. 8P Ch. 31 - Prob. 9P Ch. 31 - Scientific work is currently under way to...Ch. 31 - Prob. 11P Ch. 31 - Prob. 12P Ch. 31 - Prob. 13P Ch. 31 - Prob. 14P Ch. 31 - Prob. 15P Ch. 31 - Prob. 16P Ch. 31 - A coil formed by wrapping 50 turns of wire in the...Ch. 31 - Prob. 18P Ch. 31 - Prob. 19P Ch. 31 - Prob. 20P Ch. 31 - Prob. 21P Ch. 31 - Prob. 22P Ch. 31 - Prob. 23P Ch. 31 - A small airplane with a wingspan of 14.0 m is...Ch. 31 - A 2.00-m length of wire is held in an eastwest...Ch. 31 - Prob. 26P Ch. 31 - Prob. 27P Ch. 31 - Prob. 28P Ch. 31 - Prob. 29P Ch. 31 - Prob. 30P Ch. 31 - Prob. 31P Ch. 31 - Prob. 32P Ch. 31 - Prob. 33P Ch. 31 - Prob. 34P Ch. 31 - Prob. 35P Ch. 31 - Prob. 36P Ch. 31 - Prob. 37P Ch. 31 - Prob. 38P Ch. 31 - Prob. 39P Ch. 31 - Prob. 40P Ch. 31 - Prob. 41P Ch. 31 - Prob. 42P Ch. 31 - Prob. 43P Ch. 31 - Prob. 44P Ch. 31 - Prob. 45P Ch. 31 - Prob. 46P Ch. 31 - Prob. 47P Ch. 31 - Prob. 48P Ch. 31 - The rotating loop in an AC generator is a square...Ch. 31 - Prob. 50P Ch. 31 - Prob. 51AP Ch. 31 - Prob. 52AP Ch. 31 - Prob. 53AP Ch. 31 - Prob. 54AP Ch. 31 - Prob. 55AP Ch. 31 - Prob. 56AP Ch. 31 - Prob. 57AP Ch. 31 - Prob. 58AP Ch. 31 - Prob. 59AP Ch. 31 - Prob. 60AP Ch. 31 - Prob. 61AP Ch. 31 - Prob. 62AP Ch. 31 - Prob. 63AP Ch. 31 - Prob. 64AP Ch. 31 - Prob. 65AP Ch. 31 - Prob. 66AP Ch. 31 - Prob. 67AP Ch. 31 - A conducting rod moves with a constant velocity in...Ch. 31 - Prob. 69AP Ch. 31 - Prob. 70AP Ch. 31 - Prob. 71AP Ch. 31 - Prob. 72AP Ch. 31 - Prob. 73AP Ch. 31 - Prob. 74AP Ch. 31 - Prob. 75AP Ch. 31 - Prob. 76AP Ch. 31 - Prob. 77AP Ch. 31 - Prob. 78AP Ch. 31 - Prob. 79CP Ch. 31 - Prob. 80CP Ch. 31 - Prob. 81CP Ch. 31 - Prob. 82CP Ch. 31 - Prob. 83CP

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The reason for oscillation decay.

Solution Summary: The author explains that eddy currents in aluminum sheet set up a magnetic field that opposes the oscillations. Aluminum sheet is neutralized and not attracted to the magnet.

Videos

The reason for oscillation decay.

Want to see the full answer?

Chapter 31 Solutions