Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 32, Problem 19P
To determine
Ray diagram for a plane mirror.
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A light ray is incident in water (nw = 1.33) at an angle of 35° on an interface with flint glass (ng = 1.6). Compute the transmission angle. If a ray is incident on the same interface but from the glass side and if the transmission angle needs to be 35°, calculate the angle of incidence
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Chapter 32 Solutions
Physics for Scientists and Engineers
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- The figure shows a refracted light beam in linseed oil making an angle of ? = 34.0° with the normal line NN'. The index of refraction of linseed oil is 1.48. (a) Determine the angle ?. (b) Determine the angle ?'.arrow_forwardThe index of refraction of the core of a typical fiber optic is ncore = 1.46; the cladding has nclad = 1.4. Calculate the critical angles for the total internal reflection icrit and αcritarrow_forwardCalculate the angle of refraction at the air/core interface, r . critical angle, c and incident angle at the core/cladding interface, i . Will this light ray propagate down the fiber? You have the following data: nair = 1, ncore = 1.46, ncladding =1.43, incident =12o r = 8.2o, c = 78.4o, i = 81.8olight will propagate Formula summery Index of Refraction n= n sin 01= n, sin 0, o = sin1(2) Snell's Law Critical Angle Acceptance angle a= sin1 Numerical Aperture NA = sin a = ni- nịarrow_forward
- What is the critical angle in degrees for light traveling from zircon to a medium with index of refraction n=1.45? Give your answer with 3 sig fig.arrow_forwardWhen a light ray crosses from water into glass, it emerges at an angle of 30° with respect to the normal of the interface. What is its angle of incidence? I used Snell's Law to find the angle of incidence as 34.8 degrees (rounded to 3 sig fig), using index of refraction for water as 1.333 and for glass as 1.52. However, the answer was marked as wrong. Could you please explain steps for solving to get theta as approximately 42 degrees?arrow_forwardA ray of light travels from air and enters into a translucent medium A with an incidenceangle of 10 degrees. This medium is characterized by an index of refraction of nA = 1.3. Inanother experiment, the same ray travels from air into medium B and at the same incidenceangle. Here n B = 1.05. Which medium will refract the ray at a higher angle?arrow_forward
- The critical angle from rock salt into air is 40.5o. What is the index of refraction for rock salt. (1.54)arrow_forwardA laser beam is incident from the air at an angle of 30.00 to the vertical onto a solution of Karo syrup in water. If the beam is refracted to 19.24 to the vertical, what is the index of refraction of the syrup solution? Assume that you just have the Karo syrup and air. Don't worry about water. So, the light (in air) strikes the surface of the syrup at an angle of 30 degrees wrt the surface normal, and it refracts into the syrup at an angle of 19.24 degrees wrt a surface normal.arrow_forwardSpecifically question 2 for question 1 I found Ra = .334m, but I'm unsure of how to realate it do the Radius (R) of curvature of the mirror. (1) Assume the intensity of sunlight is 1.00 kW/m2 at the surface of Earth. A highly reflecting concave mirroron the surface of Earth is to produce a power of at least 400 W at the image point. Assume the disk of theSun subtends an angle of 0.533◦ as seen from the surface of Earth, and that the mirror is pointed straight atthe center of the Sun, with the focus between the Sun and the front of the mirror. Calculate the requiredradius Ra of the circular area of the mirror. (2) For the mirror in (2)(d), suppose the light intensity at the image is now to be at least 150 kW/m2. Findthe required relationship between Ra and the radius of curvature R of the mirror.arrow_forward
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