Chapter 3.2, Problem 27PPS

To determine

To find: The zero of a given function $f\left(x\right)=10-3x$ by graphing.

Answer to Problem 27PPS

The required zero of the given function $f\left(x\right)=10-3x$ is $\frac{10}{3}$ .

Explanation of Solution

Given information:

The given function $f\left(x\right)=10-3x$

Calculation:

Make a table to graph the function.

x	$f\left(x\right)=10-3x$	$f\left(x\right)$	$\left(x,f\left(x\right)\right)$
-2	$f\left(-2\right)=10-3\left(-2\right)$	16	$\left(-2,16\right)$
0	$f\left(0\right)=10-3\left(0\right)$	10	$\left(0,10\right)$
4	$f\left(4\right)=10-3\left(4\right)$	-2	$\left(4,-2\right)$

The graph intersects the x-axis at $\frac{10}{3}$ or 3.333. So, the zero is $\frac{10}{3}$